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OregonDuck

  • one year ago

MEDAL AND FAN GROUPING BY FACTORING 2x^2+4+1+4

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  1. OregonDuck
    • one year ago
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    plz help

  2. Nnesha
    • one year ago
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    is it 4x +1x ?

  3. Nnesha
    • one year ago
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    2x^2 +4x+1x +4 like this ?

  4. OregonDuck
    • one year ago
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    2x^2 +4x+1x +4 yes like that

  5. hybrik
    • one year ago
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    Combine 4x and x to make 5x, then you will have 2x^2+5x+4

  6. OregonDuck
    • one year ago
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    no factoring by grouping

  7. OregonDuck
    • one year ago
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    plz list the steps

  8. Nnesha
    • one year ago
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    nice make a group of two terms |dw:1437747748496:dw| what is common in red box ?

  9. hybrik
    • one year ago
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    Oh okay, find the common term in each binomial

  10. OregonDuck
    • one year ago
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    2

  11. Nnesha
    • one year ago
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    2 and ??

  12. OregonDuck
    • one year ago
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    1

  13. hybrik
    • one year ago
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    As nnesha said, the first box would have 2x, the 2nd box would have 1

  14. Nnesha
    • one year ago
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    cute and ? what about variable

  15. OregonDuck
    • one year ago
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    ????

  16. Nnesha
    • one year ago
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    x^2 is same as x times x so x is also common

  17. hybrik
    • one year ago
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    @Oregon the first box has a common term of 2x, there is an x^2 and x in first box

  18. OregonDuck
    • one year ago
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    ok yeah

  19. Nnesha
    • one year ago
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    |dw:1437747924145:dw| take out common factor 2x what will go in the parentheses ?

  20. hybrik
    • one year ago
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    So you would have \[2X(x+2) + 1(x+4)\]

  21. OregonDuck
    • one year ago
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    yeah what he said

  22. hybrik
    • one year ago
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    To get the parathenses inside, you have to divide the binomial by 2x

  23. OregonDuck
    • one year ago
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    ok

  24. hybrik
    • one year ago
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    Using that you have to group the remainders (2x and 1) to get (2x+1)(x+2)(x+4)

  25. Nnesha
    • one year ago
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    i'll let him help good luck

  26. OregonDuck
    • one year ago
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    so what is the answer?

  27. hybrik
    • one year ago
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    (2X+1)(X+2)(X+4)

  28. OregonDuck
    • one year ago
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    thanks man

  29. hybrik
    • one year ago
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    Yw

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