## OregonDuck one year ago MEDAL AND FAN GROUPING BY FACTORING 2x^2+4+1+4

1. OregonDuck

plz help

2. Nnesha

is it 4x +1x ?

3. Nnesha

2x^2 +4x+1x +4 like this ?

4. OregonDuck

2x^2 +4x+1x +4 yes like that

5. hybrik

Combine 4x and x to make 5x, then you will have 2x^2+5x+4

6. OregonDuck

no factoring by grouping

7. OregonDuck

plz list the steps

8. Nnesha

nice make a group of two terms |dw:1437747748496:dw| what is common in red box ?

9. hybrik

Oh okay, find the common term in each binomial

10. OregonDuck

2

11. Nnesha

2 and ??

12. OregonDuck

1

13. hybrik

As nnesha said, the first box would have 2x, the 2nd box would have 1

14. Nnesha

cute and ? what about variable

15. OregonDuck

????

16. Nnesha

x^2 is same as x times x so x is also common

17. hybrik

@Oregon the first box has a common term of 2x, there is an x^2 and x in first box

18. OregonDuck

ok yeah

19. Nnesha

|dw:1437747924145:dw| take out common factor 2x what will go in the parentheses ?

20. hybrik

So you would have \[2X(x+2) + 1(x+4)\]

21. OregonDuck

yeah what he said

22. hybrik

To get the parathenses inside, you have to divide the binomial by 2x

23. OregonDuck

ok

24. hybrik

Using that you have to group the remainders (2x and 1) to get (2x+1)(x+2)(x+4)

25. Nnesha

i'll let him help good luck

26. OregonDuck

27. hybrik

(2X+1)(X+2)(X+4)

28. OregonDuck

thanks man

29. hybrik

Yw