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is it 4x +1x ?
2x^2 +4x+1x +4 like this ?
2x^2 +4x+1x +4 yes like that
Combine 4x and x to make 5x, then you will have 2x^2+5x+4
no factoring by grouping
plz list the steps
nice make a group of two terms |dw:1437747748496:dw| what is common in red box ?
Oh okay, find the common term in each binomial
2 and ??
As nnesha said, the first box would have 2x, the 2nd box would have 1
cute and ? what about variable
x^2 is same as x times x so x is also common
@Oregon the first box has a common term of 2x, there is an x^2 and x in first box
|dw:1437747924145:dw| take out common factor 2x what will go in the parentheses ?
So you would have \[2X(x+2) + 1(x+4)\]
yeah what he said
To get the parathenses inside, you have to divide the binomial by 2x
Using that you have to group the remainders (2x and 1) to get (2x+1)(x+2)(x+4)
i'll let him help good luck
so what is the answer?