OregonDuck
  • OregonDuck
MEDAL AND FAN GROUPING BY FACTORING 2x^2+4+1+4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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OregonDuck
  • OregonDuck
plz help
Nnesha
  • Nnesha
is it 4x +1x ?
Nnesha
  • Nnesha
2x^2 +4x+1x +4 like this ?

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More answers

OregonDuck
  • OregonDuck
2x^2 +4x+1x +4 yes like that
hybrik
  • hybrik
Combine 4x and x to make 5x, then you will have 2x^2+5x+4
OregonDuck
  • OregonDuck
no factoring by grouping
OregonDuck
  • OregonDuck
plz list the steps
Nnesha
  • Nnesha
nice make a group of two terms |dw:1437747748496:dw| what is common in red box ?
hybrik
  • hybrik
Oh okay, find the common term in each binomial
OregonDuck
  • OregonDuck
2
Nnesha
  • Nnesha
2 and ??
OregonDuck
  • OregonDuck
1
hybrik
  • hybrik
As nnesha said, the first box would have 2x, the 2nd box would have 1
Nnesha
  • Nnesha
cute and ? what about variable
OregonDuck
  • OregonDuck
????
Nnesha
  • Nnesha
x^2 is same as x times x so x is also common
hybrik
  • hybrik
@Oregon the first box has a common term of 2x, there is an x^2 and x in first box
OregonDuck
  • OregonDuck
ok yeah
Nnesha
  • Nnesha
|dw:1437747924145:dw| take out common factor 2x what will go in the parentheses ?
hybrik
  • hybrik
So you would have \[2X(x+2) + 1(x+4)\]
OregonDuck
  • OregonDuck
yeah what he said
hybrik
  • hybrik
To get the parathenses inside, you have to divide the binomial by 2x
OregonDuck
  • OregonDuck
ok
hybrik
  • hybrik
Using that you have to group the remainders (2x and 1) to get (2x+1)(x+2)(x+4)
Nnesha
  • Nnesha
i'll let him help good luck
OregonDuck
  • OregonDuck
so what is the answer?
hybrik
  • hybrik
(2X+1)(X+2)(X+4)
OregonDuck
  • OregonDuck
thanks man
hybrik
  • hybrik
Yw

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