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- OregonDuck

factoring by grouping
2x^+4x+1+4

- OregonDuck

my answer is (2x+1)(x+2)(x+4)

- OregonDuck

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## More answers

- OregonDuck

- Flvs.net

Need help?

- OregonDuck

yes plz

- Flvs.net

I like your answer, it looks good to me.

- Flvs.net

7th advanced, you?

- Flvs.net

Oh really?

- Flvs.net

I was in public school advanced too.

- mathmate

@OregonDuck
If the answer is (2x+1)(x+2)(x+4)
the question should have been 2x^3+13x^2+22x+8
Do you still want to know \(how\) to solve it?

- OregonDuck

yes plz

- OregonDuck

@mathmate yes plz

- mathmate

We note that all coefficients are positives, therefore so are the factors.
The leading coeff. is 2, and the constant term is 8, so the possible factors are
1/2, 1,2,4, and 8.
we can try group them assuming a factor of x+2
2x^3+13x^2+22x+8
=2x^3+4x^2 + 9x^2+18x + 4x+8
=2x^2(x+2) + 9x(x+2) + 4(x+2)
and it seems to work well, so
=(x+2)(2x^2+9x+4)
factor the quadratic the same way, if you want:
=(x+2)(2x^2+8x + x+4)
=(x+2)(x+4)(2x+1)

- OregonDuck

so (x+2)(x+4)(2x+1) is the answer?

- mathmate

Yes, for the following question:
2x^3+13x^2+22x+8

- OregonDuck

NO WHAT IS THE ANSWER FOR 2x^+4x+1+4

- mathmate

you cannot factor
2x^+4x+1+4
because it is not a polynomial.
exponent is missing, and I suspect there are typos. Please check the question.

- mathmate

It also shows that you have not made any attempt to solve the problem, when you have posted your question for over half an hour and not realize that there are typos.

- OregonDuck

no 2x^2+4x+1+4

- mathmate

Are you sure about the +1+4 part?
The problem could have been written 2x^2+4x+5

- OregonDuck

yes i am sure

- mathmate

There are no rational factors for the problem 2x^2+4x+5.

- OregonDuck

k if it was written this way then the answer would be?

- mathmate

There are no rational factors for the problem 2x^2+4x+5.

- OregonDuck

then my answer was right then for 2x^+4x+1+4 right?

- OregonDuck

or prime?

- mathmate

what was your answer?

- OregonDuck

(2x+1)(x+2)(x+4)

- pooja195

#CAUGHT XD you got the answer and now you are presenting it here lol

- mathmate

Your "answer" expands to a cubic polynomial.
You're given a quadratic polynomial to factor, so your "answer" cannot be right.
I already gave you the question that corresponds to your "answer".

- OregonDuck

so it is prime?

- mathmate

There are no rational factors, as I said earlier.

- mathmate

Just to satisfy my curiosity, can you tell me how you obtained the answer
(2x+1)(x+2)(x+4)
to
"factor 2x^+4x+1+4" ?

- mathmate

The reason I said there are no rational factors is because the expression
2x^2+4x+5
can be factored into
(x+1+sqrt(3/2)i)(x+1-sqrt(3/2)i)
where i is the complex number where i^2=-1
by completing the square!

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