anonymous
  • anonymous
Given the sequence -1, 2, -4, 8.... What is the 10th term? Write the number only.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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hybrik
  • hybrik
This has a formula to this
anonymous
  • anonymous
Well first you have to find the common ratio
Jadeishere
  • Jadeishere
-1 * -2 = 2 2 * -2 = -4 -4 * -2 = 8 8 * -2 = -16 -16 * -2 = 32 you just multiply the last number in the sequence by -2 each time :)

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More answers

anonymous
  • anonymous
okay
hybrik
  • hybrik
-16. 32, -64, 128, -256, 512 is the answer [512]
anonymous
  • anonymous
There actually is a formula. an = a1*r^(n-1)
hybrik
  • hybrik
@ComputerNerd Like i said, its a arithmetic sequence
hybrik
  • hybrik
It has a formula
hybrik
  • hybrik
a1 is the first number in sequence
anonymous
  • anonymous
@hybrik its actually a geometric sequence
anonymous
  • anonymous
Write the common ratio for the sequence: 12,6,3,\frac{3}{2},... Write the number only. I'm stuck on this one as well
hybrik
  • hybrik
"\frac{3}{2}"?
anonymous
  • anonymous
3/2
hybrik
  • hybrik
The ratio is 1/2
hybrik
  • hybrik
Either you can do this logically or the arithmetic sequence formula
anonymous
  • anonymous
Identify the 10th term for the sequence: 12,6,3,\frac{3}{2},... Write the answer as an integer or fraction. I'm stuck on this one as well
anonymous
  • anonymous
it's the same pattern as the other
hybrik
  • hybrik
@ComputerNerd I noticed when I was using the formula
anonymous
  • anonymous
XD
hybrik
  • hybrik
3/4, 3/8, 3/16, 3/32, 3/64, 3/128 is the answer, 3/128, by the way, Geometric sequences have to do with Multiplying/Dividing patterns, Arithmetic has to do with Adding / Subtracting
Jadeishere
  • Jadeishere
or you could just do it the easy way @Aliypop and do what I said... Lol @ComputerNerd you don't always need to do the formula if there's a simpler way
anonymous
  • anonymous
@Jadeishere It's always best to know the formula. Your method is okay for terms lower in the sequence but would take too long for terms like 100th term.
anonymous
  • anonymous
okay

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