can someone please help?

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A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: Which of the following could be used to calculate the total volume of grains that can be stored in the silo?
If i am picturing the thing right, it is the vvolume of a cylinder plus the volume of the cone
|dw:1437755024017:dw|

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Yes Total Volume = Volume Cylinder + Volume Cone
Cylinder - height = 8 ft , radius = 2 ft Cone - height = 1.5 ft, radius = 2 ft
I got \[\pi(2ft)^2(8ft)+\frac{ 1 }{ 3 } \pi(2ft)^2(9.5ft-8ft)\]
\[Volume = [\pi*r^2*h _{cyl}] + [\frac{ 1 }{ 3 }\pi*r^2*h _{cone}]\]
yep, looks good
Could you help me with some more?
sure
What is the weight (in grams) of a liquid that exactly fills a 202.0 milliliter container if the density of the liquid is 0.685grams over milliliter? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.
weight = newtons, mass= grams.
nvm
Given: Volume = 202.0 mL Density = 0.685 g / mL Find: mass [g]
Density = mass / volume so mass = density * volume
I'm really confused lol
Just remember, the density is a mass per unit of volume Density = mass / volume
multiplying both sides by volume mass = volume x density
I got 138.37
|dw:1437755681677:dw|
right
I have one more that I need help with.
sure
A cone has a diameter of 8 centimeters and a height that is 4 times the diameter. Using 3.14 for pi, which of the following can be used to calculate the volume of the cone?
i agree with you because you work really explains well
v = (1/3) * pi * r^2 * h
diameter = 8, so radius = 4 height = 4*diameter = 4*8 = 32
My answer is: \[\frac{ 1 }{ 3 }(3.14)(8cm)^2(32cm)\]
yep, and as a check, your units come out to cm^3 which is correct for a Volume
yep
thank you so much!
no prob , anytime

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