## anonymous one year ago Hey guys it would be awesome if someone could help... Thank You A candy bar box is in the shape of a triangular prism. The volume of the box is 2,400 cubic centimeters. http://learn.flvs.net/webdav/assessment_images/educator_mjmath2_v14/mjmath2_%20test2_m5_g4_p.jpg Part A: What is the height of the box? Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)

1. anonymous

@DanJS

2. anonymous

@Deeezzzz

3. DanJS

Links to signed in things dont work.. but

4. anonymous
5. DanJS

|dw:1437756105426:dw|

6. anonymous

A triangular prism is shown with base of triangle labeled 16 cm, sides of triangles labeled 17 cm, and length of the box equal to 20 cm.

7. DanJS

Cant link pages that you signed into , im guessing, does not work

8. anonymous

does that help

9. anonymous

the descri[tion

10. DanJS

yes

11. anonymous

great

12. DanJS

|dw:1437756241528:dw|

13. anonymous

perfect

14. DanJS

The volume of that shape , is just the area of the triangular face times the extruded length of the box

15. DanJS

$V = 1/2*base*height*depth$

16. DanJS

To find the height, need to work with the triangle like this...

17. anonymous

proceed

18. DanJS

|dw:1437756382708:dw|

19. DanJS

So the height, is found with the pythagorean theorem 17^2 = 8^2 + h^2

20. anonymous

can i help

21. DanJS

$V = 1/2*base*height*depth$ $V = 1/2 * 16 * \sqrt{17^2-8^2} * 20$

22. anonymous

yes of course @kittylover1234

23. anonymous

that seem right i agree

24. DanJS

oh, they gave you the volume at the start, so you could have figured h, without all the triangle things... V = 2400 = 1/2 * 16 * h * 20

25. anonymous

yep so good so far

26. anonymous

give me a sec im trying to understand

27. DanJS

either way, the height comes out the same...k

28. anonymous

ummm ook...

29. DanJS

For the Surface Area, you have to add up the area of all the sides, all the dimensions are given

30. DanJS

2 triangles, 3 rectangles

31. anonymous

so the hieght is 15 right?

32. DanJS

right

33. anonymous

ok then for the surfcae area i would have to add up all the areas

34. anonymous

35. DanJS

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36. anonymous

what did you guys get

37. anonymous

what is it kitty ;)

38. DanJS

didnt calcualte

39. anonymous

me niether

40. anonymous

mine was wrong dang

41. anonymous

calculated wrong

42. DanJS

1240

43. anonymous

that what you got

44. DanJS

$S.A. = 2[\frac{ 1 }{ 2 }]*16*15 + [20*17]+[20*17]+[20*16]$

45. anonymous

I got 1,320

46. DanJS

2 triangles, 3 rectangles

47. anonymous

does any one agree

48. anonymous

49. anonymous

right**

50. DanJS

|dw:1437757284740:dw|

51. anonymous

Yup your def Right Dan Thanks so much both of you...!! @DanJS @kitty_lover1234

52. DanJS

welcome

53. anonymous

welcome