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anonymous
 one year ago
A tea bag is shaped like a regular square pyramid. Each leg of the base is 4 cm, and the height is 5 cm. Find the VOLUME of the tea bag.
anonymous
 one year ago
A tea bag is shaped like a regular square pyramid. Each leg of the base is 4 cm, and the height is 5 cm. Find the VOLUME of the tea bag.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Select one: a. 26.7 cm^3 b. 40 cm^3 c. 36.7 cm^3 d. 24.5 cm^3 Incorrect

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437759228283:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0\(\large V_{pyramid} = \dfrac{1}{3}Bh\) The volume of a pyramid is onethird the area of the base times height. Since your pyramid has a square base, \(B = s^2 = (4 ~cm)^2\) Find the area of the base, multiply it by the height and divide by 3.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm sorry i put the wrong question up here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A tea bag is shaped like a regular square pyramid. Each leg of the base is 4 cm, and the slant height is 5 cm. What are the lateral area & surface area of the tea bag?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a. 40 cm^2 ; 52.6 cm^2 b. 40 cm^2 ; 56 cm^2 c. 36.7 cm^2 ; 56 cm^2 d. 36.6 cm^2 ; 52.6 cm^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you think you can help with this one

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Sure. Let's draw this new question first.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The slant height of a pyramid is the height of any triangle that is one of the pyramid's lateral faces.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437759762207:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The total surface area of the pyramid is the sum of the following two components of the surface area: 1. the area of the base 2. the lateral area, which is the sum of the areas of all lateral faces Ok so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be between a&b?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The area of the base is simply the area of a square of side 4 cm. The lateral area is the sum of the areas of the 4 congruent triangles that are the sides of the pyramid. Each triangular face has a base of 4 cm and a height of 5 cm.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Let's find the area of one triangular face: \(A = \dfrac{bh}{2} = \dfrac{(4~cm)(5~cm)}{2} = 10~cm^2\) Each triangular face has an area of 10 cm^2 What is the area of all 4 triangular faces combined?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did i get it correct?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The area of the sides, the lateral area, is 40 cm^2. That is correct.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0What is the area of the base? It is a square with a 4 cm side. A = s^2 = (4 cm)^2 = 16 cm^2 The area of the base is 16 cm^2 The total surface area is 40 cm^2 + 16 cm^2 = 56 cm^2 The answer is b. 40 cm^2; 56 cm^2
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