A community for students.
Here's the question you clicked on:
 0 viewing
fefetasprites
 one year ago
22. 1/2+3/t=5/8
fefetasprites
 one year ago
22. 1/2+3/t=5/8

This Question is Closed

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You can multiply both sides by the LCD to get rid of all denominators. What is the LCD of 2, t, and 8?

fefetasprites
 one year ago
Best ResponseYou've already chosen the best response.1It's 2t, right? That's what I used and the answer came out weird. Is it 8t?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1No. You need the smallest quantity that is divisible by 2, t, and 8. 2t is divisible by 2 and t, but it is not divisible by 8. What is the smallest quantity that is divisible by 2, t, and 8?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Yes. Now we multiply both sides by 8t. This way we will get rid of all denominators. \(8t \left( \dfrac{1}{2} + \dfrac{3}{t} \right)= 8t \left( \dfrac{5}{8} \right)\) Ok?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Now we distribute the 8t on the left, and we multiply the 8t on the right. \(\dfrac{8t}{1} \left( \dfrac{1}{2} + \dfrac{3}{t} \right)= \dfrac{8t}{1} \left( \dfrac{5}{8} \right)\) \( \dfrac{8t}{2} + \dfrac{8t \times 3}{t} = \dfrac{8t \times 5}{8} \)

fefetasprites
 one year ago
Best ResponseYou've already chosen the best response.1Distribute and multiply? How I learned was to cancel out like terms. So in this question, I would cancel out the t in 8t and 3t, and cancel out the 8 in 8t and the 8 in 5/8. Does that end up with the same thing? Or am I doing something wrong?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Your idea of canceling is ok, but you need to be careful how you do it.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Now we cancel out all denominators with factors in the numerators. \( \dfrac{\cancel{8}4t}{\cancel{2}1} + \dfrac{8\cancel{t} \times 3}{\cancel{t} 1} = \dfrac{\cancel{8}t \times 5}{\cancel{8}1} \) \(4t + 24 = 5t\)

fefetasprites
 one year ago
Best ResponseYou've already chosen the best response.1Alright, so now you just do basic algebra and solve t, right?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You are correct that the 8t on the left multiplies the fraction 3/t. the t's cancel out leaving just 3 * 8 = 24. You can;t forget to also multiply 8t by the fraction 1/2. That is why it is a good idea to distribute first, then cancel.

fefetasprites
 one year ago
Best ResponseYou've already chosen the best response.1Okay, thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.