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anonymous
 one year ago
City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was –3° C. What was the temperature of City A and City B on that day?
City A was 5° C, and City B was 4° C.
City A was 3° C, and City B was –1° C.
City A was 8° C, and City B was –3° C.
City A was 5° C, and City B was –5° C.
anonymous
 one year ago
City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was –3° C. What was the temperature of City A and City B on that day? City A was 5° C, and City B was 4° C. City A was 3° C, and City B was –1° C. City A was 8° C, and City B was –3° C. City A was 5° C, and City B was –5° C.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The problem is giving you two equations here: 4a=3b+8 a2b=3 First isolate 'a' a=2b3 Then plug that into equation one 4(2b3)=3b+8 8b12=3b+8 5b=20 b=4 Plug 'b' into easiest equation for finding 'a' a=2(4)3 a=83 a=5 Answer: Temperature of city A=5 and city B=4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank alot can you help me alot
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