unicwaan
  • unicwaan
Can someone help me answer a precalculus question please?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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unicwaan
  • unicwaan
Find the angle between the given vectors to the nearest tenth of a degree. u = <2, -4>, v = <3, -8>
unicwaan
  • unicwaan
@EducationsFinest
unicwaan
  • unicwaan
@Vocaloid

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anikhalder
  • anikhalder
You can write u as 2i -4j and v as 3i -8j. Then you can apply the dot product rule to find the angle. Take a look at this page: http://www.wikihow.com/Find-the-Angle-Between-Two-Vectors Or take a look at these videos. It will really make your base strong. https://www.khanacademy.org/math/linear-algebra/vectors_and_spaces
IrishBoy123
  • IrishBoy123
you don't have to re-write them, this is really good compact notation you are using: \(\large \vec u = <2, -4>, \vec v = <3, -8>\) for \(\large \vec u = , \vec v = \), we have \(\large \vec u \bullet \vec v = u_x \times v_x + u_y \times v_y = |\vec u||\vec v| cos \theta\). \(\large \theta \) is the angle between these vectors. \(\large |\vec u|\) is the magnitude of \(\large \vec u\) and equals \(\large \sqrt {u_x^2 + u_y^2}\), ditto for \(\large |\vec v|\). that's all you need to answer this, but you should always check first for some trickery in the question, eg where they are clearly parallel.
IrishBoy123
  • IrishBoy123
@anikhalder thanks for the medal! have one back :p
anikhalder
  • anikhalder
Thank you very much. I really appreciate your explanation and I hope rather than the medals our mutual friend here won't be having troubles finding the angle between vectors anymore :)))
IrishBoy123
  • IrishBoy123
cool!
unicwaan
  • unicwaan
Thank you all!

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