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vera_ewing
 one year ago
If 5.25 mL of an unknown HCl sample was titrated with 25.3 mL of a 0.00100 M solution of NaOH to its equivalence point, what is the initial concentration of the acid?
A. 4.64 × 10^3 M
B. 4.82 × 10^3 M
C. 8.28 × 10^4 M
D. 2.08 × 10^2 M
vera_ewing
 one year ago
If 5.25 mL of an unknown HCl sample was titrated with 25.3 mL of a 0.00100 M solution of NaOH to its equivalence point, what is the initial concentration of the acid? A. 4.64 × 10^3 M B. 4.82 × 10^3 M C. 8.28 × 10^4 M D. 2.08 × 10^2 M

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vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0@JoannaBlackwelder I think it's A or B.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2What calcs did you use?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0I couldn't figure out which ones to use, so I asked for help and someone said either A or B. I'm not sure what he did.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2Ok, can you write out the acidbase reaction?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I have it written down right now.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2Ok, what did you get the molar ratios of the acid and base to be?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait it's B! Haha sorry :) thanks!

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2Yep, good job. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont think it is B I got a different value @vera_ewing

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0It's B. I got it right :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How come, I got D, how did you do?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2Find the moles of the base, and since the reaction is equimolar in the acid and base, the acid needs the same number of moles. @Cuanchi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was using the formula V1M1=V2M2 and I got D its something wrong if I use the formula @vera_ewing?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.2That is the same formula I used....not sure why we get different answers.
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