zmudz one year ago Given that $$\log_{4n} 40\sqrt{3} = \log_{3n} 45$$, find $$n^3$$.

you should get to $$(\frac{4}{3})^y = \frac{40 \sqrt{3}}{45}$$ by letting $$y = log_{4n}.... = log_{3n} ......$$ to find y, fiddle around with $$\frac{40 \sqrt{3}}{45}$$ in a calculator. for example $$(\frac{40 \sqrt{3}}{45})^2 = \frac{64}{27}$$ may be a smarter way to solve for y but that gets it going nicely