24. 2c/c-4 - 2/1=4/c+5 I know the answer is supposed to be c=-14 but I'm not really sure what the LCD is

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

24. 2c/c-4 - 2/1=4/c+5 I know the answer is supposed to be c=-14 but I'm not really sure what the LCD is

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\frac{ 2c }{ c-4 }-2=\frac{ 4 }{ c+5 }\]
LCD = least common denominator = (c-4)*(c+5)
I don't understand how that is the LCD, can you please explain?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

@Vocaloid are you still online? I really need help, sorry
the denominator of the first term is (c-4), correct? the denominator of 2 is 1 the denominator of the third term is (c+5) multiply these together to find the LCD (c-4)*(c+5)*1
Okay, so then I have to multiply the other terms by that? Like: \[(c-4*c+5) \frac{ 2c }{c-4 }-(c-4*c+5)2=(c-4*c+5)\frac{ 4 }{ c+5 }\] Is this correct?
you need to multiply each term by the quantity that will make the denominator equal to (c-4)*(c+5)*1 for example, the first term is 2c/(c-4). since we already have (c-4) in the denominator, we have to multiply by (c+5)/(c+5) to make the denominator equal to (c+5)*(c-4)
|dw:1437776145191:dw|
|dw:1437776222377:dw|
|dw:1437776306510:dw|
since all the denominators are the same now, we can cancel out the denominators and look at the numerators only now (c+5)*2c - 2(c-4)(c+5) = 4*(c-4) and now we can solve for c
Oh, okay, I see what you're saying sort of So multiplied that would all be \[2c^{2}+10c-2c+8-2c-10c=4c-16\] so i combine like terms and then I just solve for x?
yes
Double check your work. There is an error on the left of the equal sign. The c^2 term should of disappeared, plus there may be other errors.
@Vocaloid thank you so much for helping!! @radar was I supposed to cancel out the top c in 2c/c-4 along with cancelling the c-4?
After the combining in the numerator your fractions should appear as:|dw:1437783584881:dw|
|dw:1437783743735:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question