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Are these different equations?
I would just like to know how to graph it
To graph the first one, Plug in points and use a table to graph it. For the second one, the y intercept is -4, so plot a point at (0,-4) then since the slope is 1, rise/run = go up 1 unit and right one unit (1,-3) for the next point. then graph those two points. First one is a exponential function.
oh! Okay thanks!
would a point for one of them be (-1,-5) ??
@Sandy781 For the 1st or 2nd equation
@Sandy781 dont forget to hit that medal button --------------------------->
@Sandy781 the 2nd one
So that is a point correct?
Which system of equations is represented by the graph?
@Sandy781 "So that is a point correct?" it is a ordered pair that is part of the 2nd function
idk the graph sorta looks like this
1. y = x + 4, over x + 2 y = x + 4 2. y = x plus 4, over x plus 2 y = x − 4 3. y = x minus 4, over x plus 2 y = x + 4 4. y = x minus 4, over x plus 2 y = x − 4
those are the answer choices
Well the "y=x-4" is one of them
So A and C is eliminated
ok, I agree
@hybrik so what would be the answer?
Plug in points on the graph that are on there, is one of the exponential graph have the (-1,5) pair in it?
x-4/x-2 = y, -1-4/-1-2 = -5, -5/-3 = -5?
-1+4/-1+2 = 3/1
whoops, so B!
Im checking, are you sure the exponential function had the point (-1, -5)?
yeah the graph had the points (-1,-5) and (4,0)
maybe we should call for backup?
@Sandy thats the linear line or the exponential line?
i'm guessing d
Can you give me the exact image?