will give medals but pleaseeee help.
Solve for x: 4 − (x + 2) < −3(x + 4)
x < −7
x > −7
x < −9
x > −9

- anonymous

- schrodinger

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- anonymous

the first one

- calculusxy

This is basically solving for x in a regular equation.
So what you would just do is instead of having the less than symbol, you would place the equal sign.

- anonymous

@calculusxy wait ill do the work and show you where i am stuck at

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## More answers

- calculusxy

Okay

- anonymous

\[ 4-(x+2)<-3x-6\]

- anonymous

@calculusxy ^^^^

- anonymous

i don't know how to do with the other side do i take away the brackets and flip the sign of 4 to + and add the like terms ?

- anonymous

after the negative sign there is a 1 so multiply negative one by x and 2

- anonymous

so it would be -1x -2 ? @joquez14

- calculusxy

Just like what @joquez14 said.
what we can think is that before the parentheses, there is a -1 (negative because of the minus sign).
\[4-1(x+2) <-3x + 12\]
that means that you would have to do \[-1 \times x = -x\]and \[-1 \times 2 = -2\]

- calculusxy

Now we can simplify it even further wit those two terms. \[-4 -x-2<-3x-12\]

- calculusxy

Sorry i meant -12 not +12

- anonymous

okay so we add together -4 and -2
@calculusxy

- calculusxy

yes to simplify that side

- calculusxy

combine the like terms to make solving this easier

- anonymous

okay so we add the x's

- calculusxy

so this is where you need to really cancel out an x from a side.

- anonymous

so it would be 6<-2x

- calculusxy

\[-4-x-2=-3x - 12\]
\[-6 - x=-3x - 12\]
\[-6 =-2x - 12\]

- calculusxy

yes you're correct

- anonymous

but then the answer would 4 and none of my answer choices are 4 ? did i do an error ?

- anonymous

****-3 i mean

- calculusxy

what are your answer choices then?

- anonymous

they are at the top

- calculusxy

oh sorry :\

- anonymous

its not supposed to ve - 2x i thought i think its supposed to be - 4x

- calculusxy

@joquez14 if we did -3 + 1 it would equal to -2

- anonymous

yup thats what I'm getting -2

- anonymous

why you add one x was negative so u souldnt have added an positive 1

- anonymous

-1x+-3x ? @joquez14

- anonymous

ohhh -4

- anonymous

my point exactly

- anonymous

but how

- anonymous

aren't you suppose to do the inverse

- anonymous

im not to sure since were combining like terms

- anonymous

I wish I could give you all medals. You all have the right idea, it just looks like you got mixed up with the combining
4 − (x + 2) < −3(x + 4)
Start by distributing
4 - x - 2 < -3x - 12
Combine like terms on the left
2 - x < -3x - 12
Add 3x to both sides
2 + 2x < -12
Subtract 2 from both sides
2x < -14
Divide both sides by 2
x < -7

- anonymous

oh yeah ur right

- anonymous

thank you so much guys literally all of you have been such a tremendous helppppppppp @joquez14 @calculusxy and thanks for clearing it up @peachpi

- anonymous

np

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