the first one
This is basically solving for x in a regular equation. So what you would just do is instead of having the less than symbol, you would place the equal sign.
@calculusxy wait ill do the work and show you where i am stuck at
i don't know how to do with the other side do i take away the brackets and flip the sign of 4 to + and add the like terms ?
after the negative sign there is a 1 so multiply negative one by x and 2
so it would be -1x -2 ? @joquez14
Just like what @joquez14 said. what we can think is that before the parentheses, there is a -1 (negative because of the minus sign). \[4-1(x+2) <-3x + 12\] that means that you would have to do \[-1 \times x = -x\]and \[-1 \times 2 = -2\]
Now we can simplify it even further wit those two terms. \[-4 -x-2<-3x-12\]
Sorry i meant -12 not +12
okay so we add together -4 and -2 @calculusxy
yes to simplify that side
combine the like terms to make solving this easier
okay so we add the x's
so this is where you need to really cancel out an x from a side.
so it would be 6<-2x
\[-4-x-2=-3x - 12\] \[-6 - x=-3x - 12\] \[-6 =-2x - 12\]
yes you're correct
but then the answer would 4 and none of my answer choices are 4 ? did i do an error ?
****-3 i mean
what are your answer choices then?
they are at the top
oh sorry :\
its not supposed to ve - 2x i thought i think its supposed to be - 4x
@joquez14 if we did -3 + 1 it would equal to -2
yup thats what I'm getting -2
why you add one x was negative so u souldnt have added an positive 1
-1x+-3x ? @joquez14
my point exactly
aren't you suppose to do the inverse
im not to sure since were combining like terms
I wish I could give you all medals. You all have the right idea, it just looks like you got mixed up with the combining 4 − (x + 2) < −3(x + 4) Start by distributing 4 - x - 2 < -3x - 12 Combine like terms on the left 2 - x < -3x - 12 Add 3x to both sides 2 + 2x < -12 Subtract 2 from both sides 2x < -14 Divide both sides by 2 x < -7
oh yeah ur right
thank you so much guys literally all of you have been such a tremendous helppppppppp @joquez14 @calculusxy and thanks for clearing it up @peachpi