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anonymous

  • one year ago

WHAT EVER U WANT ILL GIVE NEED HELP Samantha puts an initial $500 into a savings account. The account has a 4% annual compound interest rate. What is the function that best represents Samantha's account and how much does she have in savings after 5 years? Round your answer to the nearest dollar. Hint: Use the formula, f(x) = P(1 + r)x. f(x) = 500(1.4)x, $2,689 f(x) = 500(0.04)x, $512 f(x) = 500(1.04)x, $608 f(x) = 500(1.04)x, $527

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  1. anonymous
    • one year ago
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    @nonon

  2. anonymous
    • one year ago
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    In the formula: r is the rate, P is the initial amount, x is the number of years so just plug in 0.04 for r and 500 for P. f(x) = 500(1.04)^x plug in 5 for x $608 phew

  3. anonymous
    • one year ago
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    I want a teddy bear

  4. anonymous
    • one year ago
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    THANK U FOLLOW ME AT JHERRERA (INSTAGRAM) AND IM SRY I CANT GIVE U A TEDDY BEAR XD

  5. anonymous
    • one year ago
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    :,(

  6. anonymous
    • one year ago
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    can U help me with another one @nonon

  7. anonymous
    • one year ago
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    suuure

  8. anonymous
    • one year ago
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    The sides of a square are three to the power of two sevenths inches long. What is the area of the square? nine to the power of four sevenths square inches three to the power of four sevenths square inches three to the power of the fraction four over forty nine square inches nine to the power of the fraction four over forty nine square inches

  9. anonymous
    • one year ago
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    3^(2/7) ? or (3^2)/7?

  10. anonymous
    • one year ago
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  11. anonymous
    • one year ago
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    here is the screenshot

  12. anonymous
    • one year ago
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    @nonon

  13. anonymous
    • one year ago
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    SORRY I ALMOST DOSED OFF WAIT A SECOND

  14. anonymous
    • one year ago
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    ok ok um if the bases are the same you can add powers think of it as 3^(2/7) * 3^(2/7)

  15. anonymous
    • one year ago
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    so yeah 3^(2/7 + 2/7) is the answer

  16. anonymous
    • one year ago
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    these are the answers nine to the power of four sevenths square inches three to the power of four sevenths square inches three to the power of the fraction four over forty nine square inches nine to the power of the fraction four over forty nine square inches

  17. anonymous
    • one year ago
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    yeah add them

  18. anonymous
    • one year ago
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    B

  19. anonymous
    • one year ago
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    yeah

  20. anonymous
    • one year ago
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    :D teddy bear

  21. anonymous
    • one year ago
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    btw realize you can just plug it in the calculator or even google and see which ones match

  22. anonymous
    • one year ago
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    sry im acting retartded

  23. anonymous
    • one year ago
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    Naaaah just helping you in case you have trouble outside of internet :P

  24. anonymous
    • one year ago
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    you got instagram

  25. anonymous
    • one year ago
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    I don't

  26. anonymous
    • one year ago
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    OMG SO SRY ONE MORE PLEASE Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average rate of change of each section. (4 points) Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

  27. anonymous
    • one year ago
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    wait is this physics???

  28. anonymous
    • one year ago
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    Idk im in 8th but i take 9 and 10th grade math

  29. anonymous
    • one year ago
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    wait are there any powers in the equation?

  30. anonymous
    • one year ago
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    no

  31. anonymous
    • one year ago
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    I'm so confused do you have screenshot?

  32. anonymous
    • one year ago
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  33. anonymous
    • one year ago
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    oh x is a power of 3

  34. anonymous
    • one year ago
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    you meant 2(3)^x

  35. anonymous
    • one year ago
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    partA: sectionA: 6-2=4 sectionB: 54-18=36 part B: 36/4 = 9 9 times greater

  36. anonymous
    • one year ago
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    yeah you just had to plug in each number for x than find the difference

  37. anonymous
    • one year ago
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    Thanks jaredhm29 that was great algebra review (not being sarcastic) :D

  38. anonymous
    • one year ago
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    THANK U SO MUCH U WERE SOOOOOOO HELPFUL

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