Juan jogs each day from his house to a local park, and then he jogs back along the same route. On his way to the park, he averages 4 miles per hour. On his way home, he averages 6 miles per hour. If the total trip takes 1 1/2 hours, which equation can be used to find x, the distance from Juan’s house to the park? x/4+x/6=1 x/4+x/6=1 1/2 4x6x=1 1/2 4x+6x=1

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Juan jogs each day from his house to a local park, and then he jogs back along the same route. On his way to the park, he averages 4 miles per hour. On his way home, he averages 6 miles per hour. If the total trip takes 1 1/2 hours, which equation can be used to find x, the distance from Juan’s house to the park? x/4+x/6=1 x/4+x/6=1 1/2 4x6x=1 1/2 4x+6x=1

Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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speed 4 miles /hr means he covers 4 miles in an hour covers 1 mile in =1/4 hr covers x miles in=(1/4 )*x hrs=x/4 hrs for return journey speed 6 miles/hr means he covers 6 miles in one hour covers 1 mile in=1/6 hrs covers x miles in=(1/6)*x hrs Total time taken=x/4 +x/6=?

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