## anonymous one year ago A system of equations is shown below: 6x – 5y = 5 3x + 5y = 4 The x-coordinate of the solution to this system of equations is _____.

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1. anonymous

@horsegirl27

2. anonymous

@HELP-ME-PLZ

3. pooja195

\begin{bmatrix}6x-5y=5 \\3x+5y=4\end{bmatrix}

4. pooja195

{Multiply:3x+5y=4 by 2 $\begin{bmatrix}6x-5y=5 \\6x+10y=8\end{bmatrix}$ $\huge~\rm~6x+10y=8$

5. UsukiDoll

why not use elimination method?

6. pooja195

Thats what im using as u can see

7. UsukiDoll

6x – 5y = 5 3x + 5y = 4 if you add these equations together, we can get rid of the y's.

8. UsukiDoll

then we can solve for x

9. pooja195

Or that works too ;P 6+3=? 5+4=?

10. anonymous

can yu help me more

11. UsukiDoll

so by solving for x we can place x = ? into one of the equations and solve for y xD I'm just finding the best method and seeing that -5y and 5y is already there, why not cancel them out first?

12. UsukiDoll

I want to see if you understand the concepts.. so can you please add 6x – 5y = 5 3x + 5y = 4 together and solve for x? @elmo23

13. anonymous

-1

14. UsukiDoll

close 9x=9 (divide both sides by 9) x = 1

15. UsukiDoll

so now we can just plug in x = 1 into one of our equations...

16. UsukiDoll

let's plug in x = 1 in here 3x + 5y = 4 so we have 3(1)+5y=4 3+5y=4

17. UsukiDoll

so we need to solve for y

18. UsukiDoll

so subtract 3 on both sides (first step) and then divide both sides by 5 (second step)

19. anonymous

it (1,/5)

20. UsukiDoll

3+5y=4 -3 -3 5y=1 y= 1/5 correct so x = 1 and y = 1/5 we can check that these values are correct by plugging them back into the equation

21. anonymous

(1, 1/5) like that

22. UsukiDoll

yeah, but the question isn't asking to put it in order paired form which is (1, 1/5) so we can just leave it as x = 1 and y = 1/5 :)

23. anonymous

so i need to put that as the answer ? or no

24. UsukiDoll

yes just put x = 1 and y = 1/5. I'll plug the values back in the equations to prove that we have found the right values of x and y

25. anonymous

thanks can u help me again

26. UsukiDoll

6x – 5y = 5 3x + 5y = 4 so for x = 1 and y = 1/5 $6(1)-5(\frac{1}{5})=5$ $6-(\frac{5}{5})=5$ $6-1=5$ $5=5$ 3x + 5y = 4 $3(1)+5(\frac{1}{5})=4$ $3+(\frac{5}{5})=4$ $3+1=4$ $4=4$

27. UsukiDoll

yeah sure.

28. anonymous

Nick works two jobs to pay for college. He tutors for $15 per hour and also works as a bag boy for$8 per hour. Due to his class and study schedule, Nick is only able to work up to 20 hours per week but must earn at least $150 per week. If t represents the number of hours Nick tutors and b represents the number of hours he works as a bag boy, which system of inequalities represents this scenario? t + b greater than or equal to 20 15t + 8b = 150 t + b less than or greater to 20 15t + 8b greater than or equal to 150 t + b less than or greater to 20 15t + 8b less than or greater to 150 None of the systems shown represent this scenario. 29. UsukiDoll uh oh. I'm not good at these word problems. @rishavraj 30. anonymous oh ok im trying to get a good grade so i can get every thing good 31. anonymous @pooja195 32. pooja195 Repost it someone else will help im not good with these 33. anonymous ight 34. anonymous @hero 35. pooja195 I keep getting this t+b = 20 b=bag boy hours t=tutor hours 15t+8b = 150 We know he earns %15 per hour for the tutoring job and$8 for bag boy in total he earns \$150 We know this but since none match it would be none of the scienerios