A system of equations is shown below:
6x – 5y = 5
3x + 5y = 4
The x-coordinate of the solution to this system of equations is _____.

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- anonymous

- chestercat

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- anonymous

- anonymous

@HELP-ME-PLZ

- pooja195

\begin{bmatrix}6x-5y=5 \\3x+5y=4\end{bmatrix}

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## More answers

- pooja195

{Multiply:3x+5y=4 by 2
\[\begin{bmatrix}6x-5y=5 \\6x+10y=8\end{bmatrix}\]
\[\huge~\rm~6x+10y=8\]

- UsukiDoll

why not use elimination method?

- pooja195

Thats what im using as u can see

- UsukiDoll

6x – 5y = 5
3x + 5y = 4
if you add these equations together, we can get rid of the y's.

- UsukiDoll

then we can solve for x

- pooja195

Or that works too ;P
6+3=?
5+4=?

- anonymous

can yu help me more

- UsukiDoll

so by solving for x we can place x = ? into one of the equations and solve for y xD
I'm just finding the best method and seeing that -5y and 5y is already there, why not cancel them out first?

- UsukiDoll

I want to see if you understand the concepts.. so can you please add
6x – 5y = 5
3x + 5y = 4
together and solve for x?
@elmo23

- anonymous

-1

- UsukiDoll

close
9x=9 (divide both sides by 9)
x = 1

- UsukiDoll

so now we can just plug in x = 1 into one of our equations...

- UsukiDoll

let's plug in x = 1 in here
3x + 5y = 4
so we have
3(1)+5y=4
3+5y=4

- UsukiDoll

so we need to solve for y

- UsukiDoll

so subtract 3 on both sides (first step)
and then divide both sides by 5 (second step)

- anonymous

it (1,/5)

- UsukiDoll

3+5y=4
-3 -3
5y=1
y= 1/5
correct
so x = 1 and y = 1/5
we can check that these values are correct by plugging them back into the equation

- anonymous

(1, 1/5) like that

- UsukiDoll

yeah, but the question isn't asking to put it in order paired form which is (1, 1/5) so we can just leave it as x = 1 and y = 1/5 :)

- anonymous

so i need to put that as the answer ? or no

- UsukiDoll

yes just put x = 1 and y = 1/5. I'll plug the values back in the equations to prove that we have found the right values of x and y

- anonymous

thanks can u help me again

- UsukiDoll

6x – 5y = 5
3x + 5y = 4
so for x = 1 and y = 1/5
\[6(1)-5(\frac{1}{5})=5\]
\[6-(\frac{5}{5})=5\]
\[6-1=5\]
\[5=5\]
3x + 5y = 4
\[3(1)+5(\frac{1}{5})=4\]
\[3+(\frac{5}{5})=4\]
\[3+1=4\]
\[4=4\]

- UsukiDoll

yeah sure.

- anonymous

Nick works two jobs to pay for college. He tutors for $15 per hour and also works as a bag boy for $8 per hour. Due to his class and study schedule, Nick is only able to work up to 20 hours per week but must earn at least $150 per week. If t represents the number of hours Nick tutors and b represents the number of hours he works as a bag boy, which system of inequalities represents this scenario?
t + b greater than or equal to 20
15t + 8b = 150
t + b less than or greater to 20
15t + 8b greater than or equal to 150
t + b less than or greater to 20
15t + 8b less than or greater to 150
None of the systems shown represent this scenario.

- UsukiDoll

uh oh. I'm not good at these word problems. @rishavraj

- anonymous

oh ok im trying to get a good grade so i can get every thing good

- anonymous

- pooja195

Repost it someone else will help im not good with these

- anonymous

ight

- anonymous

- pooja195

I keep getting this
t+b = 20
b=bag boy hours
t=tutor hours
15t+8b = 150
We know he earns %15 per hour for the tutoring job and $8 for bag boy in total he earns $150
We know this but since none match it would be none of the scienerios

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