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i think its the second one
The left part is correct. For the right side you have to square the radius
so.... it would be the first one then?
okay, thanks! can you help me with another one?
Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠QRO? Circle N is shown with a quadrilateral OPQR inscribed inside it. Angle O is labeled x plus 16. Angle P is not labeled. Angle Q is labeled 6x minus 4. Angle R is labeled 2x plus 16. m∠QPO + (x + 16)° + (6x − 4)° = 360° m∠QPO = (x + 16)° + (6x − 4)° m∠QPO + (2x + 16)° = 180° m∠QPO = (6x − 4)° + (2x + 16)°
I'm not sure how to find this one though. do you need the picture of it or are you okay?
yeah i'm gonna need the pic
okay hold up
there you go :)
ok let me think on it for a second.
the third one is true. opposite angles in an inscribed quadrilateral are supplementary
that's the answer? how did you get it? can you help me understand? :)
woah. okay, i think i get it!
i have two more questions... if that's okay?
Gina drew a circle with right triangle PRQ inscribed in it, as shown below: The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center and angle R is a right angle. Arc QR measures 100 degrees. If the measure of arc QR is 100°, what is the measure of angle PQR?
do you need the pic?
Start by finding QPR, which is half the intercepted arc |dw:1437793660355:dw|
the arc is 100°. The angle is half of 100, what's that?
then since the angles in a triangle add up to 180 we can find PQR |dw:1437793992807:dw|
so would i do 180 - 90 - 50 = 40??
so that is the answer? just... 40??
oh. awesome, okay.. last one :)
The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees and angle CBA measures 56 degrees. What is the measure of angle ACB?
so i would have to do C= 176-112/2 = 32?
okay, awesome! thnak you so much!!!
i fanned you :)