Stormswan
  • Stormswan
Can someone please check my work?? I will give a medal :) A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle? (x − 7)^2 + (y − 8)^2 = 121 (x − 7)^2 + (y − 8)^2 = 11 (x + 7)^2 + (y + 8)^2 = 121 (x + 7)^2 + (y + 8)^2 = 11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Stormswan
  • Stormswan
i think its the second one
anonymous
  • anonymous
The left part is correct. For the right side you have to square the radius
Stormswan
  • Stormswan
so.... it would be the first one then?

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More answers

anonymous
  • anonymous
yes
Stormswan
  • Stormswan
okay, thanks! can you help me with another one?
anonymous
  • anonymous
ok
Stormswan
  • Stormswan
Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠QRO? Circle N is shown with a quadrilateral OPQR inscribed inside it. Angle O is labeled x plus 16. Angle P is not labeled. Angle Q is labeled 6x minus 4. Angle R is labeled 2x plus 16. m∠QPO + (x + 16)° + (6x − 4)° = 360° m∠QPO = (x + 16)° + (6x − 4)° m∠QPO + (2x + 16)° = 180° m∠QPO = (6x − 4)° + (2x + 16)°
Stormswan
  • Stormswan
I'm not sure how to find this one though. do you need the picture of it or are you okay?
anonymous
  • anonymous
yeah i'm gonna need the pic
Stormswan
  • Stormswan
okay hold up
Stormswan
  • Stormswan
1 Attachment
Stormswan
  • Stormswan
there you go :)
anonymous
  • anonymous
ok let me think on it for a second.
anonymous
  • anonymous
the third one is true. opposite angles in an inscribed quadrilateral are supplementary
Stormswan
  • Stormswan
that's the answer? how did you get it? can you help me understand? :)
anonymous
  • anonymous
|dw:1437793000757:dw|
anonymous
  • anonymous
P is
Stormswan
  • Stormswan
woah. okay, i think i get it!
Stormswan
  • Stormswan
i have two more questions... if that's okay?
anonymous
  • anonymous
ok
Stormswan
  • Stormswan
Gina drew a circle with right triangle PRQ inscribed in it, as shown below: The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center and angle R is a right angle. Arc QR measures 100 degrees. If the measure of arc QR is 100°, what is the measure of angle PQR?
Stormswan
  • Stormswan
do you need the pic?
anonymous
  • anonymous
yes
Stormswan
  • Stormswan
anonymous
  • anonymous
Start by finding QPR, which is half the intercepted arc |dw:1437793660355:dw|
Stormswan
  • Stormswan
so.....
anonymous
  • anonymous
the arc is 100°. The angle is half of 100, what's that?
Stormswan
  • Stormswan
50. oh
anonymous
  • anonymous
then since the angles in a triangle add up to 180 we can find PQR |dw:1437793992807:dw|
Stormswan
  • Stormswan
so would i do 180 - 90 - 50 = 40??
anonymous
  • anonymous
yep
Stormswan
  • Stormswan
so that is the answer? just... 40??
anonymous
  • anonymous
yes
Stormswan
  • Stormswan
oh. awesome, okay.. last one :)
Stormswan
  • Stormswan
The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees and angle CBA measures 56 degrees. What is the measure of angle ACB?
Stormswan
  • Stormswan
Stormswan
  • Stormswan
@peachpi could you help with this last one? i gave you a medal!
anonymous
  • anonymous
|dw:1437795151338:dw|
Stormswan
  • Stormswan
so 112?
anonymous
  • anonymous
yes, |dw:1437795291949:dw|
Stormswan
  • Stormswan
so i would have to do C= 176-112/2 = 32?
anonymous
  • anonymous
yes
Stormswan
  • Stormswan
okay, awesome! thnak you so much!!!
Stormswan
  • Stormswan
i fanned you :)
anonymous
  • anonymous
you're welcome!

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