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Stormswan

  • one year ago

Can someone please check my work?? I will give a medal :) A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle? (x − 7)^2 + (y − 8)^2 = 121 (x − 7)^2 + (y − 8)^2 = 11 (x + 7)^2 + (y + 8)^2 = 121 (x + 7)^2 + (y + 8)^2 = 11

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  1. Stormswan
    • one year ago
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    i think its the second one

  2. anonymous
    • one year ago
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    The left part is correct. For the right side you have to square the radius

  3. Stormswan
    • one year ago
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    so.... it would be the first one then?

  4. anonymous
    • one year ago
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    yes

  5. Stormswan
    • one year ago
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    okay, thanks! can you help me with another one?

  6. anonymous
    • one year ago
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    ok

  7. Stormswan
    • one year ago
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    Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠QRO? Circle N is shown with a quadrilateral OPQR inscribed inside it. Angle O is labeled x plus 16. Angle P is not labeled. Angle Q is labeled 6x minus 4. Angle R is labeled 2x plus 16. m∠QPO + (x + 16)° + (6x − 4)° = 360° m∠QPO = (x + 16)° + (6x − 4)° m∠QPO + (2x + 16)° = 180° m∠QPO = (6x − 4)° + (2x + 16)°

  8. Stormswan
    • one year ago
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    I'm not sure how to find this one though. do you need the picture of it or are you okay?

  9. anonymous
    • one year ago
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    yeah i'm gonna need the pic

  10. Stormswan
    • one year ago
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    okay hold up

  11. Stormswan
    • one year ago
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  12. Stormswan
    • one year ago
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    there you go :)

  13. anonymous
    • one year ago
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    ok let me think on it for a second.

  14. anonymous
    • one year ago
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    the third one is true. opposite angles in an inscribed quadrilateral are supplementary

  15. Stormswan
    • one year ago
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    that's the answer? how did you get it? can you help me understand? :)

  16. anonymous
    • one year ago
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    |dw:1437793000757:dw|

  17. anonymous
    • one year ago
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    P is <QPO and R is 2x+16, so QPO + 2x + 16 = 180

  18. Stormswan
    • one year ago
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    woah. okay, i think i get it!

  19. Stormswan
    • one year ago
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    i have two more questions... if that's okay?

  20. anonymous
    • one year ago
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    ok

  21. Stormswan
    • one year ago
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    Gina drew a circle with right triangle PRQ inscribed in it, as shown below: The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center and angle R is a right angle. Arc QR measures 100 degrees. If the measure of arc QR is 100°, what is the measure of angle PQR?

  22. Stormswan
    • one year ago
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    do you need the pic?

  23. anonymous
    • one year ago
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    yes

  24. Stormswan
    • one year ago
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  25. anonymous
    • one year ago
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    Start by finding QPR, which is half the intercepted arc |dw:1437793660355:dw|

  26. Stormswan
    • one year ago
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    so.....

  27. anonymous
    • one year ago
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    the arc is 100°. The angle is half of 100, what's that?

  28. Stormswan
    • one year ago
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    50. oh

  29. anonymous
    • one year ago
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    then since the angles in a triangle add up to 180 we can find PQR |dw:1437793992807:dw|

  30. Stormswan
    • one year ago
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    so would i do 180 - 90 - 50 = 40??

  31. anonymous
    • one year ago
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    yep

  32. Stormswan
    • one year ago
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    so that is the answer? just... 40??

  33. anonymous
    • one year ago
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    yes

  34. Stormswan
    • one year ago
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    oh. awesome, okay.. last one :)

  35. Stormswan
    • one year ago
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    The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees and angle CBA measures 56 degrees. What is the measure of angle ACB?

  36. Stormswan
    • one year ago
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  37. Stormswan
    • one year ago
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    @peachpi could you help with this last one? i gave you a medal!

  38. anonymous
    • one year ago
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    |dw:1437795151338:dw|

  39. Stormswan
    • one year ago
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    so 112?

  40. anonymous
    • one year ago
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    yes, |dw:1437795291949:dw|

  41. Stormswan
    • one year ago
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    so i would have to do C= 176-112/2 = 32?

  42. anonymous
    • one year ago
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    yes

  43. Stormswan
    • one year ago
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    okay, awesome! thnak you so much!!!

  44. Stormswan
    • one year ago
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    i fanned you :)

  45. anonymous
    • one year ago
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    you're welcome!

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