- Stormswan

Can someone please check my work?? I will give a medal :)
A circle is centered at (7, 8) and has a radius of 11. Which of the following is the equation for this circle?
(x − 7)^2 + (y − 8)^2 = 121
(x − 7)^2 + (y − 8)^2 = 11
(x + 7)^2 + (y + 8)^2 = 121
(x + 7)^2 + (y + 8)^2 = 11

- jamiebookeater

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- Stormswan

i think its the second one

- anonymous

The left part is correct. For the right side you have to square the radius

- Stormswan

so.... it would be the first one then?

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## More answers

- anonymous

yes

- Stormswan

okay, thanks! can you help me with another one?

- anonymous

ok

- Stormswan

Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠QRO?
Circle N is shown with a quadrilateral OPQR inscribed inside it. Angle O is labeled x plus 16. Angle P is not labeled. Angle Q is labeled 6x minus 4. Angle R is labeled 2x plus 16.
m∠QPO + (x + 16)° + (6x − 4)° = 360°
m∠QPO = (x + 16)° + (6x − 4)°
m∠QPO + (2x + 16)° = 180°
m∠QPO = (6x − 4)° + (2x + 16)°

- Stormswan

I'm not sure how to find this one though. do you need the picture of it or are you okay?

- anonymous

yeah i'm gonna need the pic

- Stormswan

okay hold up

- Stormswan

##### 1 Attachment

- Stormswan

there you go :)

- anonymous

ok let me think on it for a second.

- anonymous

the third one is true. opposite angles in an inscribed quadrilateral are supplementary

- Stormswan

that's the answer? how did you get it? can you help me understand? :)

- anonymous

|dw:1437793000757:dw|

- anonymous

P is

- Stormswan

woah. okay, i think i get it!

- Stormswan

i have two more questions... if that's okay?

- anonymous

ok

- Stormswan

Gina drew a circle with right triangle PRQ inscribed in it, as shown below:
The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center and angle R is a right angle. Arc QR measures 100 degrees.
If the measure of arc QR is 100°, what is the measure of angle PQR?

- Stormswan

do you need the pic?

- anonymous

yes

- Stormswan

##### 1 Attachment

- anonymous

Start by finding QPR, which is half the intercepted arc
|dw:1437793660355:dw|

- Stormswan

so.....

- anonymous

the arc is 100°. The angle is half of 100, what's that?

- Stormswan

50. oh

- anonymous

then since the angles in a triangle add up to 180 we can find PQR
|dw:1437793992807:dw|

- Stormswan

so would i do 180 - 90 - 50 = 40??

- anonymous

yep

- Stormswan

so that is the answer? just... 40??

- anonymous

yes

- Stormswan

oh. awesome, okay.. last one :)

- Stormswan

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X:
The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 176 degrees and angle CBA measures 56 degrees.
What is the measure of angle ACB?

- Stormswan

##### 1 Attachment

- Stormswan

@peachpi could you help with this last one? i gave you a medal!

- anonymous

|dw:1437795151338:dw|

- Stormswan

so 112?

- anonymous

yes,
|dw:1437795291949:dw|

- Stormswan

so i would have to do C= 176-112/2 = 32?

- anonymous

yes

- Stormswan

okay, awesome! thnak you so much!!!

- Stormswan

i fanned you :)

- anonymous

you're welcome!

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