Describe the patterns shown by the erosion data measurements shown for each of the beaches in the table. Between which years will the beaches have approximately the same width? Assuming these rates remain constant, what can you do to get a better approximation of when the two beaches will have the same width?
Year number Western Beach width (in feet) Dunes Beach width (in feet) 0 100 20 5 90 45 10 80 70 11 78 75 12 76 80 15 70 95
@peachpi please helppp
Western Beach is losing sand, Dunes beach is gaining sand. Between 11 and 12 years Plot the data against time and draw a curve that goes through the data. Where the two lines cross is the time when both beaches are the same width.
ok i think you are correct does anyone agree with him.
I don't need to get anything wrong
@CBARREDO1 is correct
You are such a great person I always count on you to help me with me with math @peachpi thanks a lot.
You're welcome. Thank you! I appreciate that :)
I feel left out here ;-;
and thanks to you as well c
so @CBARREDO1 is this your paper or did you just do this tooday
because i don't want to copy
@CBARREDO1 don't feel left out. you did all the hard work! :)
yea definitely i just messaged him
what paper are you talking about?
the problem response you gave me
No, I just analyzed, where could I copy it from xD?
@CBARREDO1 how would i graph this on geogbra
any one knows
ldo you know what is desmos
@peachpi do you know how to graph on geogbra
I know desmos
ok how on desmos. i don't know hot to graph point only equations
sorry I don't know geobra. I don't really know how to do points on desmos.
cant be mad cause i don't know either.
you can make equations for the lines by hand or use wolframalpha to get the line between points. then graph the lines on desmos
ok let me see
im on the website and i dont know where to go
Go to wolframalpha.com There should be a box to type in. Enter this to get an equation for the first beach: line through (0,100) and (5,90)
it says y=100-2x
well is their another 2 point to do?
put that equation in desmos, and then the line comes do the same for the next
wait but aren't we trying to figure out the approx for year 11 and 12
when they will be the same width
approximation of when the two beaches will have the same width?
that's why you're graphing them. once you have the lines graphed you're looking for the intersection point, which will be between 11 and 12
but 0,100 is is year 0 while 5,90 is year 5. Year 11 and 12 are the closest, so should't we be doing year 11 and 12 then finding where intersection point is?
and how will we have two lines
please talk back
@peachpi WHAT HAPPENED
sorry didn't realize you had posted something here. You're going to have 2 different equations, one for each beach. We found the first equation is y = 100 - 2x. Find the second one using 2 points from the other beach, like (0, 20) and (5,45). As far as choosing 11 and 12, it doesn't matter. It takes 2 points to define a line, it doesn't matter which two points you use. You can use the points that correspond to 11 and 12 and the results will be the same. I just picked the two I chose because they were the top two points.
I COPY AND PASTED JUST AS IT IS HERE SO IT IS Y=5X+20 sorry about caps
ok. so the two lines you're going to graph are y = 5x + 20 and y = 100-2x
and you're looking for the intersection point
it is (11.43,77.14)
ok thank you