The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approximately what percent of the students are between 14 and 18 years old?
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we have :
mean = 15 years
SD = 2 years
let be F the distribution of the N(0,1) is the z-table,
P( 14 < Age < 18) = P( - 0.5 < (Age - mean)/SD < 1.5)
= F(1.5) - F( -0.5)
= .93319 - .30854
-----------------------> P( 14 < Age < 18) = .62465 second answer
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Wait wait wait, Can someone tell me exactly how to do this as i have 2 more questions like this one and i should probably figure out how to do them properly
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