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anonymous

  • one year ago

Please help!!! Solve -np - 90 > 30 for n. Show your work.

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  1. UsukiDoll
    • one year ago
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    for n... so we need n by itself...

  2. anonymous
    • one year ago
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    ok

  3. UsukiDoll
    • one year ago
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    alright... so we need to add what number to both sides so we have all numbers to the right

  4. UsukiDoll
    • one year ago
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    -np -90 > 30 I want all numbers to the right.. .

  5. UsukiDoll
    • one year ago
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    so how do we cancel out the 90 in the left? and have 90 on the right?

  6. anonymous
    • one year ago
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    +90

  7. UsukiDoll
    • one year ago
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    yup add 90 to both sides -np>30+90 and what's 30+90?

  8. anonymous
    • one year ago
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    120

  9. UsukiDoll
    • one year ago
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    yup so now we have -np>120 we just need to divide when dividing both sides with a negative sign we need to switch the inequality signs

  10. UsukiDoll
    • one year ago
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    now we need just an n by itself... what can we divide to both sides to make that happen?

  11. anonymous
    • one year ago
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    divide by p

  12. UsukiDoll
    • one year ago
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    yes we divide by p , but remember we want just positive n by itself so we need to divide both sides by -p and since we have a negative sign involved, the inequality sign gets switched.

  13. anonymous
    • one year ago
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    oh ok

  14. UsukiDoll
    • one year ago
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    -np >120 \[n < \frac{120}{-p}\]

  15. UsukiDoll
    • one year ago
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    though negative signs in the denominator is frowned upon :( so just place it in the numerator/ \[n < \frac{-120}{p}\]

  16. anonymous
    • one year ago
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    ok

  17. UsukiDoll
    • one year ago
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    so now we have n by itself... we're done . :)

  18. anonymous
    • one year ago
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    thank you :)

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