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mathmath333
 one year ago
Logarithm question
mathmath333
 one year ago
Logarithm question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align}&\text{express }\ \log \dfrac{a^{2/3}}{b^{5}\sqrt{c}} \hspace{.33em}\\~\\ & a.)\ \dfrac{3}{2}\log a+5\log b2\log c \hspace{.33em}\\~\\ & b.)\ \dfrac{2}{3}\log a5\log b2\log c \hspace{.33em}\\~\\ & c.)\ \dfrac{2}{3}\log a5\log b+2\log c \hspace{.33em}\\~\\ & d.)\ \dfrac{3}{2}\log a+5\log b2\log c \hspace{.33em}\\~\\ \end{align}}\)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3we need the log rules for this one... so all three of them are being used.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810148932:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\log a^\frac{ 2 }{ 3 } \log b^5\log c^\frac{ 1 }{ 2 }\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1is it option c.) ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3here's a problem .. those choices have 2 for c instead of a 1/2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3... otherwise the a and b portions are correct but one rule is needed ... exponent rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah it should be 1/2 though since c^1/2

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1except 2 is it option c.)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810300989:dw <  this rule needs to be used after doing the other 2 log rules.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i mean is option c.) correct except the rule on 2 instead of 1/2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810360573:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3wait a sec.. by elevator rule we should have a negative exponent on top..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810460826:dw < example

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810507720:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437810508756:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437810548559:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3cookie monster almost tricked me into using the elevator rule wrong ___ BAD COOKIE MONSTER! NO COOKIES FOR YOU! YOU GET GRANOLA BARS INSTEAD!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3and the elevator rule *gives granola bar*

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1what is gronola bar ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3has flax seeds in em.. and raisins.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1is it better than cookies

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3_ I think cookie man is right... with the exception of that 2 for c (not sure how they got that) \[ \large \log \dfrac{a^{2/3}}{b^{5}\sqrt{c}} \] \[ \large \log \dfrac{a^{2/3}}{b^{5}c^{\frac{1}{2}}} \] \[\large \log a^{\frac{2}{3}} \log b^5logc^{\frac{1}{2}}\] \[\frac{2}{3}\log a5\log b(\frac{1}{2}) \log c\] \[\frac{2}{3}\log a5\log b+\frac{1}{2} \log c \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3errr awkward... no refunds ^^

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3guys cookie man is right.. it was distribution towards the end that made the sign change x(

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3oh ok I guess it was the  sign... it's a bit confusing because at first when I was doing the problem it will come up as a minus... but we are also dealing with a negative exponent too ... unless that negative from the exponent and the minus sign from the log rule... is just one 

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3oh it's a combination... of the minus from the log rule and the negative exponent... x(

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1437811756674:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I'm confused for the last part... x.x any clarification? or a memory refresher... it's like the subtraction rule and exponent rule is being used at the same time for that c.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437812129408:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3oh that's what happened I got something mixed up doh! it is  1/2 log c at the end ^_^
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