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mathmath333

  • one year ago

Logarithm question

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align}&\text{express }\ \log \dfrac{a^{2/3}}{b^{5}\sqrt{c}} \hspace{.33em}\\~\\ & a.)\ \dfrac{3}{2}\log a+5\log b-2\log c \hspace{.33em}\\~\\ & b.)\ \dfrac{2}{3}\log a-5\log b-2\log c \hspace{.33em}\\~\\ & c.)\ \dfrac{2}{3}\log a-5\log b+2\log c \hspace{.33em}\\~\\ & d.)\ \dfrac{3}{2}\log a+5\log b-2\log c \hspace{.33em}\\~\\ \end{align}}\)

  2. UsukiDoll
    • one year ago
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    we need the log rules for this one... so all three of them are being used.

  3. UsukiDoll
    • one year ago
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    |dw:1437810148932:dw|

  4. anonymous
    • one year ago
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    \[\log a^\frac{ 2 }{ 3 } -\log b^5-\log c^\frac{ 1 }{ 2 }\]

  5. mathmath333
    • one year ago
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    is it option c.) ?

  6. UsukiDoll
    • one year ago
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    here's a problem .. those choices have 2 for c instead of a 1/2

  7. UsukiDoll
    • one year ago
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    ... otherwise the a and b portions are correct but one rule is needed ... exponent rule

  8. anonymous
    • one year ago
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    Yeah it should be 1/2 though since c^1/2

  9. mathmath333
    • one year ago
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    except 2 is it option c.)

  10. UsukiDoll
    • one year ago
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    |dw:1437810300989:dw| < - this rule needs to be used after doing the other 2 log rules.

  11. mathmath333
    • one year ago
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    i mean is option c.) correct except the rule on 2 instead of 1/2

  12. UsukiDoll
    • one year ago
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    |dw:1437810360573:dw|

  13. mathmath333
    • one year ago
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    option c.) -.-

  14. UsukiDoll
    • one year ago
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    wait a sec.. by elevator rule we should have a negative exponent on top..

  15. UsukiDoll
    • one year ago
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    |dw:1437810460826:dw| <-- example

  16. mathmath333
    • one year ago
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    my head hurts

  17. UsukiDoll
    • one year ago
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    |dw:1437810507720:dw|

  18. anonymous
    • one year ago
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    |dw:1437810508756:dw|

  19. UsukiDoll
    • one year ago
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    thanks @Deeezzzz

  20. UsukiDoll
    • one year ago
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    |dw:1437810548559:dw|

  21. anonymous
    • one year ago
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    correct

  22. mathmath333
    • one year ago
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    is it option b.)

  23. anonymous
    • one year ago
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    yes it is B

  24. UsukiDoll
    • one year ago
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    cookie monster almost tricked me into using the elevator rule wrong -___- BAD COOKIE MONSTER! NO COOKIES FOR YOU! YOU GET GRANOLA BARS INSTEAD!

  25. mathmath333
    • one year ago
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    my head hurts

  26. UsukiDoll
    • one year ago
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    and the elevator rule *gives granola bar*

  27. mathmath333
    • one year ago
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    what is gronola bar ?

  28. UsukiDoll
    • one year ago
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    has flax seeds in em.. and raisins.

  29. sweetburger
    • one year ago
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    LOL

  30. mathmath333
    • one year ago
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    is it better than cookies

  31. UsukiDoll
    • one year ago
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    -_- I think cookie man is right... with the exception of that 2 for c (not sure how they got that) \[ \large \log \dfrac{a^{2/3}}{b^{5}\sqrt{c}} \] \[ \large \log \dfrac{a^{2/3}}{b^{5}c^{\frac{1}{2}}} \] \[\large \log a^{\frac{2}{3}}- \log b^5-logc^{-\frac{1}{2}}\] \[\frac{2}{3}\log a-5\log b-(-\frac{1}{2}) \log c\] \[\frac{2}{3}\log a-5\log b+\frac{1}{2} \log c \]

  32. UsukiDoll
    • one year ago
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    errr awkward... no refunds ^^

  33. mathmath333
    • one year ago
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    *head bang

  34. UsukiDoll
    • one year ago
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    guys cookie man is right.. it was distribution towards the end that made the sign change x(

  35. UsukiDoll
    • one year ago
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    oh ok I guess it was the - sign... it's a bit confusing because at first when I was doing the problem it will come up as a minus... but we are also dealing with a negative exponent too ... unless that negative from the exponent and the minus sign from the log rule... is just one -

  36. UsukiDoll
    • one year ago
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    oh it's a combination... of the minus from the log rule and the negative exponent... x(

  37. UsukiDoll
    • one year ago
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    |dw:1437811756674:dw|

  38. UsukiDoll
    • one year ago
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    I'm confused for the last part... x.x any clarification? or a memory refresher... it's like the subtraction rule and exponent rule is being used at the same time for that c.

  39. anonymous
    • one year ago
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    |dw:1437812129408:dw|

  40. UsukiDoll
    • one year ago
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    oh that's what happened I got something mixed up doh! it is - 1/2 log c at the end ^_^

  41. anonymous
    • one year ago
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    Lol

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