## UsukiDoll one year ago logarithm refresher question. So suppose I have... (will draw)

1. UsukiDoll

|dw:1437812609759:dw|

2. UsukiDoll

or $\LARGE \log(\frac{a}{b^2})$ and I want to use log rules to separate them

3. UsukiDoll

would the subtraction rule and the exponent rule be used at the same time?

4. UsukiDoll

ok yes that's the subtraction rule for that problem. so now I put the exponent 2 in the front right?

5. UsukiDoll

|dw:1437812695740:dw|

6. UsukiDoll

alright... I guess I got log rules and elevator rules confused (that's why it got mashed up) so use pure log rules even those the exponent is in the denominator?

7. anonymous

Yes what are elevator rules?

8. UsukiDoll

oh the elevator rule is for negative exponents. like for example suppose we have $\LARGE x^{-2}$ since we can't have negative exponents we have to write it as $\LARGE \frac{1}{x^2}$ as in bring it downstairs

9. anonymous

Using this Log Calculator http://www.acalculator.com/logarithm-calculator-logx-logarithmic-equations.html it is easiest to make calculation for logarithms.

10. UsukiDoll

now if we have something like $\LARGE \frac{1}{x^{-2}}$ since negative exponents aren't allowed I have to change this.. bring it upstairs $\LARGE x^{-(-2)} \rightarrow x^2$

11. UsukiDoll

@post thanks but I rather do them manually :)

12. UsukiDoll

@Deeezzzz why did you delete some of your posts? I wanna give you a medal

13. UsukiDoll

ok... let's have another example ummmm $\LARGE \log(\frac{a^{6}b^{7}}{c^4})$

14. UsukiDoll

alright so all 3 log rules are being used here.

15. UsukiDoll

$\LARGE \log a^6+ \log b^7 -\log c^4$ that's the first part

16. UsukiDoll

addition and subtraction rules being used.. now for exponents $\LARGE 6\log a+ 7\log b -4 \log c$

17. UsukiDoll

ah I get it.. pure log rules ^_^ and log rules only ^_^

18. UsukiDoll

19. mathmath333

hello

20. UsukiDoll

@mathmath333 got any logs similar to what I did so I can practice?

21. mathmath333

yea

22. UsukiDoll

k.

23. mathmath333

\Large \color{black}{\begin{align} \log_{2} (9-2^{x})=10^{\log_{10} (3-x)} \end{align}}

24. UsukiDoll

not those -_-

25. UsukiDoll

the one you had earlier @mathmath333

26. mathmath333

only one question was there like that

27. mathmath333

any way that is also interesting question