## anonymous one year ago metal and fan George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two becomes unsolvable. George explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to George how the equation is still solvable and explain your reasoning.

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1. anonymous

$\frac{ 4 }{ 5 }+\frac{ 3 }{ x }=\frac{ 1 }{ 2 }$ restriction is $x \neq 0$ $\frac{ 3 }{ x }=\frac{ 1 }{ 2 }-\frac{ 4 }{ 5 }$ $\frac{ 3 }{ x }=\frac{ 5-8 }{ 10 }=-\frac{ 3 }{ 10 }$

2. anonymous

$\frac{ x }{ 3 }=-\frac{ 10 }{ 3 }$ x=?