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anonymous
 one year ago
metal and fan
George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two becomes unsolvable. George explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to George how the equation is still solvable and explain your reasoning.
anonymous
 one year ago
metal and fan George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two becomes unsolvable. George explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to George how the equation is still solvable and explain your reasoning.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4 }{ 5 }+\frac{ 3 }{ x }=\frac{ 1 }{ 2 }\] restriction is \[x \neq 0\] \[\frac{ 3 }{ x }=\frac{ 1 }{ 2 }\frac{ 4 }{ 5 }\] \[\frac{ 3 }{ x }=\frac{ 58 }{ 10 }=\frac{ 3 }{ 10 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x }{ 3 }=\frac{ 10 }{ 3 }\] x=?
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