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amyna
 one year ago
find the derivative:
y=(x^2+csc(5x))^3/2
thank you!
amyna
 one year ago
find the derivative: y=(x^2+csc(5x))^3/2 thank you!

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(y=(x^2+cosec(5x))^{3/2}\) that it? suggest you share what you have done/ what the problem is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2x^{1}2/15\csc(5x)^{1/3}\]

amyna
 one year ago
Best ResponseYou've already chosen the best response.0i used chain rule and got 3/2(x^2+csc(5x))^1/2 (2xcsc(5x)cot(5x)*5 ? i don't know if thats right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1right but + instead of  at the last term. dw:1437846650378:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1is this what you are saying? \((3/2)(x^2+csc(5x))^{1/2} (2xcsc(5x)cot(5x).5)\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1look at @Loser66 's sketch \( (cosec \ x)^\prime =  cosec \ x \ cot \ x\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1sorry, @loser66 was trying to make this point: \( d/dx (5x) = 5\). so you have: \( \frac{3}{2}(x^2+cosec(−5x))^{1/2} \ \ (2x−cosec(−5x)cot(−5x)(5)) \) \(\ = \frac{3}{2}(x^2+cosec(−5x))^{1/2} \ \ (2x+5 \ cosec(−5x)cot(−5x)) \) next, i'd be really tempted to clean out those \(5x\)'s within the trig functions but maybe you are happy

amyna
 one year ago
Best ResponseYou've already chosen the best response.0thanks! it makes more sense now!
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