anonymous
  • anonymous
Solve the interval [0,2pi): 1+sin theta=1/2 A.2pi/3, 4pi/3 B.pi/6, 5pi/6 C.pi/3, 5pi/3 D.7pi/6, 11pi/6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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cwrw238
  • cwrw238
subtract 1 from both sides of the equation: sin theta = -1/2
anonymous
  • anonymous
Do I graph sin theta =-1/2?
anonymous
  • anonymous
What does the [0,2pi) even mean?

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cwrw238
  • cwrw238
[0,2pi) means the solutions in the range 0 to 2pi radians
anonymous
  • anonymous
So can that limit my answers, or it doesn't matter?
cwrw238
  • cwrw238
first find the reference angle use your calculator to find the angle whose sine is 1/2 enter sin-1 (1/2) make sure that your calc is set to radians can you do that?
cwrw238
  • cwrw238
yes it limits the answers to angles in that range
anonymous
  • anonymous
Yeah, althoght dont I need the unit circle for that, and can graphing be another way to solve the problem?
cwrw238
  • cwrw238
you can but its easier to use calc or you can use the dtandard triangle below:- |dw:1437850039490:dw|
anonymous
  • anonymous
When I type in arcsin (1/2) I get pie/6? Is that correct?
cwrw238
  • cwrw238
yes - and you see its pi.6 from the above trianggle
anonymous
  • anonymous
Yeah, but does that mean that its a solution to the problem?
cwrw238
  • cwrw238
but the sine is -1/2 and the angles with this sine are in the 3rd and 4th quadrants
cwrw238
  • cwrw238
|dw:1437850196121:dw|
cwrw238
  • cwrw238
oh - ive written them in degrees 30 degrees = pi/6 radians
anonymous
  • anonymous
Oh!!!!, so now what?
cwrw238
  • cwrw238
|dw:1437850294435:dw|
cwrw238
  • cwrw238
thats one angle: 7pi/6 can you work out the other?
anonymous
  • anonymous
I think so, let me trie! :0 By the way thank for yoir help, really appreciated!
cwrw238
  • cwrw238
one revolution = 2pi radians
cwrw238
  • cwrw238
yw
anonymous
  • anonymous
I don't know if its correct but I get 11pi/6?
cwrw238
  • cwrw238
thats correct 2pi - pi/6 = 12pi/6 - pi/6 = 11pi/6
cwrw238
  • cwrw238
D is correct choice
anonymous
  • anonymous
Okay thanks again! :)
cwrw238
  • cwrw238
yw

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