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hayleyc24

  • one year ago

2x^4 + 2x^2 +32 can you break this down any farther? Help will be rewarded

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  1. cwrw238
    • one year ago
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    well first take 2 out = 2(x^4 + x^2 + 16)

  2. hayleyc24
    • one year ago
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    why would you take the 2 out its attached to the x squared

  3. cwrw238
    • one year ago
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    2 is the GCF of 2, 2 and 32

  4. cwrw238
    • one year ago
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    but the expression in the parentheses won't factor

  5. hayleyc24
    • one year ago
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    you've lost me and I just realized I forgot to include this f(g(x)) = and then the problem

  6. hayleyc24
    • one year ago
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    I've already solved for most of the problem would it help if I gave you the original problem?

  7. cwrw238
    • one year ago
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    lets have the whole problem then

  8. cwrw238
    • one year ago
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    yes

  9. hayleyc24
    • one year ago
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    okay give me a sec

  10. hayleyc24
    • one year ago
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    Let f(x) = x2 + x + 2 and g(x) = 2x2 + 5. Find f(g(x)). Show each step of your work.

  11. cwrw238
    • one year ago
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    oh ok what you do is replace very occurrence of x in f(x) by g(x)

  12. hayleyc24
    • one year ago
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    Plug in the g(x) equation where all the x's are in f(x). (2x^2 + 5)^2 + (2x^2 + 5) + 2 2x^4 + 5^2 + 2x^2 + 5 + 2 2x^4 + 25 +2x^2 + 7 2x^4 + 2x^2 + 32

  13. cwrw238
    • one year ago
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    f(x) = x2 + x + 2 f((g(x)) = (2x^2 + 5)^2 + 2x^2 + 5 + 2 = 4x^4 + 20x^2 + 25 + 2x^2 + 7 = 4x^4 + 22x^2 + 32

  14. cwrw238
    • one year ago
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    you didnt expand (2x^2 + 5)^2 correctly

  15. hayleyc24
    • one year ago
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    Thank you, so the 22 and 4 cannot be combined becuase of the different exponents right?

  16. cwrw238
    • one year ago
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    right

  17. hayleyc24
    • one year ago
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    Thank you thank you thank you thank you!!!!!!!!

  18. cwrw238
    • one year ago
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    yw lol

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