## anonymous one year ago Find the first six terms of the sequence. a1 = -3, an = 2 ● an-1

1. myininaya

replace n with 2

2. myininaya

$a_1=-3 \\ a_n=2 \cdot a_{n-1} \\ \text{ replacing } n \text{ with } 2 \\ a_2=2 \cdot a_{2-1} \\ a_2=2 \cdot a_1 \text {since 2-1=1} \\ \text{ now recall } a_1=-3 \\ \text{ replace } a_1 \text{ with -3 } \\ a_2=2 (-3)=-6 \text{, -6 is the second term }$

3. myininaya

try finding the 3rd term by replacing n with 3 instead of 2

4. anonymous

-12 3 -24 4 -48 5 -96 6

5. myininaya

checking... $a_3=2 \cdot a_{3-1} \\ a_3=2 \cdot a_2 \\ \text{ but remember } a_2=-6 \\ a_3=2(-6)=-12$ your third term is right anyways we are just multiplying previous term by 2 so we started with -3 -3(2)=-6 -6(2)=-12 -12(2)=-24 -24(2)=-48 -48(2)=-96 yep seems great

6. anonymous

thanks

7. anonymous

I might have a few more questions later

8. myininaya

hey on the previous question where you asked what 9+10 like was that really the question?

9. anonymous

lol, no @myininaya

10. myininaya

Like if you can give me the actual question I might be able to help you with it

11. anonymous

lol

12. anonymous

Im just studying for my semester exam so it can be any type of question. I dont have any right now tho

13. myininaya

oh ok

14. anonymous

actually I lied, I'll post a new question