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anonymous
 one year ago
Find f(5) for this sequence
f(1) = 2 and f(2) = 5, f(n) = f(1) + f(2) + f(n  1), for n > 2.
f(5) = ______
anonymous
 one year ago
Find f(5) for this sequence f(1) = 2 and f(2) = 5, f(n) = f(1) + f(2) + f(n  1), for n > 2. f(5) = ______

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.3do you understand what f(n) = f(1) + f(2) + f(n  1) means?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.3f(n) = f(1) + f(2) + f(n  1) is a rule we can use to find the value of the function for a certain n value so, let's just say we want to find f(3), where n = 3 we can use the formula f(n) = f(1) + f(2) + f(n1), giving us f(3) = f(1) + f(2) + f(31), does that make sense so far?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ok so I think you're still kind of confused on what to do after you plug in n = 5, so we have \[f(5) = f(1)+f(2)+f(51) \implies f(5)=f(1)+f(2)+f(4)\] but notice we don't have f(4) given right? We have to figure that out using the same formula.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I mean you have to use the same formula \[f(4) = f(1)+f(2)+f(41) \implies f(1)+f(2)+f(3)\] so now we need to find f(3)...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[f(5) = f(1)+f(2)+f(1)+f(2)+f(3)\] so this is what we have so far, we need to find f(3), I think you should be able to do the rest.

Empty
 one year ago
Best ResponseYou've already chosen the best response.0It's probably best to just plug in f(1) and f(2) from the very start to get the new recurrence relation: f(n+1)=f(n)+7
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