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anonymous
 one year ago
WILL MEDAL AND FAN NO LIE
Cards numbered 1, 1, 2, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 8, and 9 are placed in a bag.
If a card is drawn from the bag and then replaced 135 times, about how many times would a 6 be drawn?
A.
2
B.
9
C.
15
D.
18
anonymous
 one year ago
WILL MEDAL AND FAN NO LIE Cards numbered 1, 1, 2, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 8, and 9 are placed in a bag. If a card is drawn from the bag and then replaced 135 times, about how many times would a 6 be drawn? A. 2 B. 9 C. 15 D. 18

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2(number of 6's/total number of cards)*135

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2how many cards have 6 on them?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0there are 2 cards marked 6 out of a total of 15 cards so probability of picking a 6 in one draw is = ?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2right, and how many total cards are there?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0I mentioned that above

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2the answer isn't c, would you mind telling me how many total cards there are?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait i think its D srry

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1As Vocaloid wrote \[\Large \text{Expected Number of 6's} = \frac{\text{Number of 6's}}{\text{Total number of cards}}*135\] \[\Large \text{Expected Number of 6's} = \frac{2}{15}*135\] \[\Large \text{Expected Number of 6's} = ???\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sooo just do 2/15 x 135 :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok can u help me with more @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@automaticloveletter

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Is there a new question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea i need help with math

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Well you can ask them and just tag me in them I'm happy to help
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