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aivantettet26

  • one year ago

RECTANGULAR COMPONENTS OF A VECTOR FORCE PROBLEM.

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  1. DanJS
    • one year ago
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    .

  2. aivantettet26
    • one year ago
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  3. aivantettet26
    • one year ago
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    Sorry. Slow computer

  4. aivantettet26
    • one year ago
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    @DanJS

  5. DanJS
    • one year ago
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    I would first find the coordinate of B using the lengths given

  6. DanJS
    • one year ago
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    looks like you have to play around and find some lengths the hinge is (0,0,0,)

  7. aivantettet26
    • one year ago
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    @DanJS That's the part where I'm struggling. I'm trying to use the 45degree angle

  8. DanJS
    • one year ago
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    draw some right triangles on the disc

  9. dan815
    • one year ago
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    |dw:1437883107472:dw|

  10. dan815
    • one year ago
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    |dw:1437883228372:dw|

  11. dan815
    • one year ago
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    are u comfortable with how u got the coodinates there?

  12. dan815
    • one year ago
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    |dw:1437883524512:dw|

  13. DanJS
    • one year ago
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    haha, i went to get a drink and you done...

  14. DanJS
    • one year ago
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    statics is fun...

  15. aivantettet26
    • one year ago
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    I see. So then after getting the required lengths. we use the formula A = Axi + Ayj + Azk?

  16. dan815
    • one year ago
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    where x,y,z are the compnents of the unit vector it has to be a unit vector in the direction u want

  17. dan815
    • one year ago
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    so that the magnitude of (k*unitvector) = k where k is 500 in this case,

  18. dan815
    • one year ago
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    this is a way to see how to divide your 500 Newtons of force into its component form

  19. DanJS
    • one year ago
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    After u get the start and end points of the vector, use V =<(x2-x1) , (y2-y1), (z2-z1)> The unit vector length 1 in the direction of V is , the V over its magnitude Then multiply that by the force at A, to get the force vector, as dan did

  20. DanJS
    • one year ago
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    the v roof hat, is the unit vector of length 1

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