anonymous
  • anonymous
The position of an object at time t is given by s(t) = -4 - 2t. Find the instantaneous velocity at t = 6 by finding the derivative. How would I solve this?
Mathematics
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anonymous
  • anonymous
The position of an object at time t is given by s(t) = -4 - 2t. Find the instantaneous velocity at t = 6 by finding the derivative. How would I solve this?
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
s'(t) = -2. So s'(6) = -2
DanJS
  • DanJS
yea, there is no acceleration, it is traveling in a straight line, the velocity is the slope
DanJS
  • DanJS
a(t) = s ''(t) = 0

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anonymous
  • anonymous
@sourwing so the final answer is -2?
SolomonZelman
  • SolomonZelman
Yes, the final answer is 2. In this case, notice, the velocity is given by a line y=-2 and that means that for any value of x the veloicty is same. (and acceleration, the 2nd derivative, is 0)
SolomonZelman
  • SolomonZelman
oh, -2 (typo)
SolomonZelman
  • SolomonZelman
to make sure, one more time. the final ans is -2

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