Let Γ be the circumcircle of ΔABC and let D be the midpoint of the arc BC. Prove that below three points are collinear :
2) the incenter I of ΔABC
Stacey Warren - Expert brainly.com
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Exactly, but somehow I find below statement not so obvious
"D lies on the angle bisector of angle A"
just looking for a proof if it is easy :)
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hence AD bisects BAD
I can't answer "why not" because idk lol
By definition, \(I\) lies on the angel bisector... but not so much about the point \(D\) is known right
Ahh wait I see what you're doing, you're saying "equal chords of the same circle intercept equal angles" ?
I don't know the name of the property but it is!! if the arcs of the angles are equal, then the angles are equal.
That should do! thanks!
However, the original problem is not a piece of cake. I didn't find out the logic yet!! ha!!
Can you please help me draw out the circle center D that goes through B? I need it to prove O is the incenter of \(\triangle ABC\). Please
It is already there but hidden... just scroll down on the left hand side, do you see "Conic" section ?