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anonymous

  • one year ago

When you choose 6 different numbers from 1-53 and your numbers must match the 6 numbers later drawn (lottery) . if you buy one ticket what is the probability of winning the jackpot? Order of numbers do not matter..

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  1. anonymous
    • one year ago
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    im not sure, but i think i would be an 8.3 percent chance

  2. anonymous
    • one year ago
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    because 53/how many tickets would be 8.3, and thats chance, could be wrong but...

  3. anonymous
    • one year ago
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    because its 6 out of 53

  4. anonymous
    • one year ago
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    Thanks

  5. taramgrant0543664
    • one year ago
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    The 6/53 is the chance of one of your numbers being the same

  6. anonymous
    • one year ago
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    yup she's right nevermind its the opposite. sorry bout that

  7. taramgrant0543664
    • one year ago
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    So the odds of getting one number right is 6/53 The odds of getting the second number is 5/52 (since you can't repeat the number the total amount of numbers decrease hence going from 53 to 52) The odds of the third number is 4/51 Fourth is 3/50 Fifth is 2/49 And the sixth is 1/48 To find your chance at winning you have to multiply all those together times that by 100 and that's your percent

  8. taramgrant0543664
    • one year ago
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    Since I have to leave I'll tell you the number is 4.355x10^-6% and that is why nobody really wins cause there is pretty much no chance

  9. anonymous
    • one year ago
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    lol is basically a gimmick

  10. taramgrant0543664
    • one year ago
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    Exactly but people still go for it since there is a sliver of a chance that they could win

  11. MrNood
    • one year ago
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    @jcoury You should always consider your answers from a point of view of "is it reasonable" If there was an 8.3% chance of winning the jackpot we would all be millionaires by now

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