When you choose 6 different numbers from 1-53 and your numbers must match the 6 numbers later drawn (lottery) . if you buy one ticket what is the probability of winning the jackpot? Order of numbers do not matter..
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im not sure, but i think i would be an 8.3 percent chance
because 53/how many tickets would be 8.3, and thats chance, could be wrong but...
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The 6/53 is the chance of one of your numbers being the same
yup she's right nevermind its the opposite. sorry bout that
So the odds of getting one number right is 6/53
The odds of getting the second number is 5/52 (since you can't repeat the number the total amount of numbers decrease hence going from 53 to 52)
The odds of the third number is 4/51
Fourth is 3/50
Fifth is 2/49
And the sixth is 1/48
To find your chance at winning you have to multiply all those together times that by 100 and that's your percent
Since I have to leave I'll tell you the number is 4.355x10^-6% and that is why nobody really wins cause there is pretty much no chance
lol is basically a gimmick
Exactly but people still go for it since there is a sliver of a chance that they could win
You should always consider your answers from a point of view of "is it reasonable"
If there was an 8.3% chance of winning the jackpot we would all be millionaires by now