anonymous
  • anonymous
When you choose 6 different numbers from 1-53 and your numbers must match the 6 numbers later drawn (lottery) . if you buy one ticket what is the probability of winning the jackpot? Order of numbers do not matter..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
im not sure, but i think i would be an 8.3 percent chance
anonymous
  • anonymous
because 53/how many tickets would be 8.3, and thats chance, could be wrong but...
anonymous
  • anonymous
because its 6 out of 53

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anonymous
  • anonymous
Thanks
taramgrant0543664
  • taramgrant0543664
The 6/53 is the chance of one of your numbers being the same
anonymous
  • anonymous
yup she's right nevermind its the opposite. sorry bout that
taramgrant0543664
  • taramgrant0543664
So the odds of getting one number right is 6/53 The odds of getting the second number is 5/52 (since you can't repeat the number the total amount of numbers decrease hence going from 53 to 52) The odds of the third number is 4/51 Fourth is 3/50 Fifth is 2/49 And the sixth is 1/48 To find your chance at winning you have to multiply all those together times that by 100 and that's your percent
taramgrant0543664
  • taramgrant0543664
Since I have to leave I'll tell you the number is 4.355x10^-6% and that is why nobody really wins cause there is pretty much no chance
anonymous
  • anonymous
lol is basically a gimmick
taramgrant0543664
  • taramgrant0543664
Exactly but people still go for it since there is a sliver of a chance that they could win
MrNood
  • MrNood
@jcoury You should always consider your answers from a point of view of "is it reasonable" If there was an 8.3% chance of winning the jackpot we would all be millionaires by now

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