vera_ewing
  • vera_ewing
What is the pH of a solution with [OH-] = 2.6 × 10^-3 M?
Chemistry
chestercat
  • chestercat
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vera_ewing
  • vera_ewing
@thomaster Help please!
vera_ewing
  • vera_ewing
@jcoury help please!
anonymous
  • anonymous
doing it hold on

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anonymous
  • anonymous
okay i cant figure out how to do it with -3 but this is with -2, you you could just replace the -2 with -3 and do the same steps: HBr is a strong acid so it dissociates completely in water: HBr + H2O = H3O+ + Br- 1mol HBr = 1mol H3O+ [HBr] = 2.6*10^-2. Therefore: [H3O+] = 2.6*10^-2 What is pH? pH = -log [H3O+] pH = -log (2.6*10^-2) pH = 1.59 What is [OH-] pH + pOH = 14.00 pOH = 14.00-pH pOH = 14.00 - 1.59 pOH = 12.41 [OH-] = 10^-pOH [OH-] = 10^-12.41 [OH-] = 3.85*10^-13 There is a very simple way to work out [OH-] [H3O+] * [OH-] = 10^-14 [OH-] = (10^-14) / (2.6*10^-2) [OH-] = 3.85*10^-13 I did both methods because OI am not sure what you have been taught.
vera_ewing
  • vera_ewing
Wait but what's the answer?
anonymous
  • anonymous
3.85*10^-13 But you would have to do the steps i just showed you but with -3
vera_ewing
  • vera_ewing
These are my answer choices A. 11.41 B. 5.95 C. 2.59 D. 8.05
anonymous
  • anonymous
okay hold up. let @yamyam70 take it from here
vera_ewing
  • vera_ewing
@yamyam70 Help please!
yamyam70
  • yamyam70
@jcoury @vera_ewing this is chem! Im not good with chem! haha ILL TRY thougn
vera_ewing
  • vera_ewing
@Rushwr Please help!
yamyam70
  • yamyam70
@vera_ewing you want to get pH from [ OH- ] ? not pOH right?
vera_ewing
  • vera_ewing
Yes, what is the pH?
yamyam70
  • yamyam70
@vera_ewing working with the maths, ill post it here after haha
yamyam70
  • yamyam70
@vera_ewing We need to convert it from [OH-] to [ H+ ] from [H + ] we can get the value of pH by taking the logarithm
yamyam70
  • yamyam70
|dw:1437920001430:dw|
yamyam70
  • yamyam70
@vera_ewing There you go!
yamyam70
  • yamyam70
@jcoury I found the site where you copy pasted your answer here, that is indeed off topic, and does not help in any form. Please avoid this type of actions. thanks reference https://answers.yahoo.com/question/index?qid=20100809235159AAcCjxE
anonymous
  • anonymous
I didn't get it from that
yamyam70
  • yamyam70
It is verbatim as it seems.
vera_ewing
  • vera_ewing
Thank you so much! :)
yamyam70
  • yamyam70
Welcome :)

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