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vera_ewing

  • one year ago

What is the pH of a solution with [OH-] = 2.6 × 10^-3 M?

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  1. vera_ewing
    • one year ago
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    @thomaster Help please!

  2. vera_ewing
    • one year ago
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    @jcoury help please!

  3. anonymous
    • one year ago
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    doing it hold on

  4. anonymous
    • one year ago
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    okay i cant figure out how to do it with -3 but this is with -2, you you could just replace the -2 with -3 and do the same steps: HBr is a strong acid so it dissociates completely in water: HBr + H2O = H3O+ + Br- 1mol HBr = 1mol H3O+ [HBr] = 2.6*10^-2. Therefore: [H3O+] = 2.6*10^-2 What is pH? pH = -log [H3O+] pH = -log (2.6*10^-2) pH = 1.59 What is [OH-] pH + pOH = 14.00 pOH = 14.00-pH pOH = 14.00 - 1.59 pOH = 12.41 [OH-] = 10^-pOH [OH-] = 10^-12.41 [OH-] = 3.85*10^-13 There is a very simple way to work out [OH-] [H3O+] * [OH-] = 10^-14 [OH-] = (10^-14) / (2.6*10^-2) [OH-] = 3.85*10^-13 I did both methods because OI am not sure what you have been taught.

  5. vera_ewing
    • one year ago
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    Wait but what's the answer?

  6. anonymous
    • one year ago
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    3.85*10^-13 But you would have to do the steps i just showed you but with -3

  7. vera_ewing
    • one year ago
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    These are my answer choices A. 11.41 B. 5.95 C. 2.59 D. 8.05

  8. anonymous
    • one year ago
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    okay hold up. let @yamyam70 take it from here

  9. vera_ewing
    • one year ago
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    @yamyam70 Help please!

  10. yamyam70
    • one year ago
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    @jcoury @vera_ewing this is chem! Im not good with chem! haha ILL TRY thougn

  11. vera_ewing
    • one year ago
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    @Rushwr Please help!

  12. yamyam70
    • one year ago
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    @vera_ewing you want to get pH from [ OH- ] ? not pOH right?

  13. vera_ewing
    • one year ago
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    Yes, what is the pH?

  14. yamyam70
    • one year ago
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    @vera_ewing working with the maths, ill post it here after haha

  15. yamyam70
    • one year ago
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    @vera_ewing We need to convert it from [OH-] to [ H+ ] from [H + ] we can get the value of pH by taking the logarithm

  16. yamyam70
    • one year ago
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    |dw:1437920001430:dw|

  17. yamyam70
    • one year ago
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    @vera_ewing There you go!

  18. yamyam70
    • one year ago
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    @jcoury I found the site where you copy pasted your answer here, that is indeed off topic, and does not help in any form. Please avoid this type of actions. thanks reference https://answers.yahoo.com/question/index?qid=20100809235159AAcCjxE

  19. anonymous
    • one year ago
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    I didn't get it from that

  20. yamyam70
    • one year ago
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    It is verbatim as it seems.

  21. vera_ewing
    • one year ago
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    Thank you so much! :)

  22. yamyam70
    • one year ago
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    Welcome :)

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