Help! A rectangular plot of land has an area of 512 square feet and is 16 feet longer than it is wide. -Write a quadratic formula in the form ax^2+bx+c=0 (whose solution is the width of the plot of land) -Solve the equation

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Help! A rectangular plot of land has an area of 512 square feet and is 16 feet longer than it is wide. -Write a quadratic formula in the form ax^2+bx+c=0 (whose solution is the width of the plot of land) -Solve the equation

Mathematics
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ok, you know that: `Area of a rectangle = (rectangle's width) • (rectangle's length)` right?
now, you are also given that your length is 16 feet longer than the width. So, if you were to name your width - "x", then your length, which is given to be 16 feet longer than width, will be x+16.
YOu are given the area of this rectangle too. it is 512 (square feet)

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So, since: `Area of a rectangle = (rectangle's width) • (rectangle's length)` then, therefore: `512 = (x) • (x+16)`
When you expand that, and subtract 512 from both sides, then you got the quadratic equation in a form that you want.
if you have further questions, ask.
So the formula in the standard form would be (x)*(x+16)-512?
you got so far, x•(x+16)-512=0
you need to expand the x•(x+16) peace
So by expanding the x*(x+16) piece it would be in its standard form of x^2+16x-512 ? @SolomonZelman
yes
x²+16x-512=0 then sovle for x
factoring or completing the square would be fairly easy, but if you don't know how to do these methods or don't feel like, then you can use the quadratic formula (if you want, just ask, i will post the quadratic formula)

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