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anonymous

  • one year ago

Help! A rectangular plot of land has an area of 512 square feet and is 16 feet longer than it is wide. -Write a quadratic formula in the form ax^2+bx+c=0 (whose solution is the width of the plot of land) -Solve the equation

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  1. SolomonZelman
    • one year ago
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    ok, you know that: `Area of a rectangle = (rectangle's width) • (rectangle's length)` right?

  2. SolomonZelman
    • one year ago
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    now, you are also given that your length is 16 feet longer than the width. So, if you were to name your width - "x", then your length, which is given to be 16 feet longer than width, will be x+16.

  3. SolomonZelman
    • one year ago
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    YOu are given the area of this rectangle too. it is 512 (square feet)

  4. SolomonZelman
    • one year ago
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    So, since: `Area of a rectangle = (rectangle's width) • (rectangle's length)` then, therefore: `512 = (x) • (x+16)`

  5. SolomonZelman
    • one year ago
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    When you expand that, and subtract 512 from both sides, then you got the quadratic equation in a form that you want.

  6. SolomonZelman
    • one year ago
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    if you have further questions, ask.

  7. anonymous
    • one year ago
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    So the formula in the standard form would be (x)*(x+16)-512?

  8. anonymous
    • one year ago
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    @SolomonZelman

  9. SolomonZelman
    • one year ago
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    you got so far, x•(x+16)-512=0

  10. SolomonZelman
    • one year ago
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    you need to expand the x•(x+16) peace

  11. anonymous
    • one year ago
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    So by expanding the x*(x+16) piece it would be in its standard form of x^2+16x-512 ? @SolomonZelman

  12. SolomonZelman
    • one year ago
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    yes

  13. SolomonZelman
    • one year ago
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    x²+16x-512=0 then sovle for x

  14. SolomonZelman
    • one year ago
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    factoring or completing the square would be fairly easy, but if you don't know how to do these methods or don't feel like, then you can use the quadratic formula (if you want, just ask, i will post the quadratic formula)

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