anonymous
  • anonymous
THREE QUESTIONS HELP GIVING MEDALS 1.) Let u = <5, 6>, v = <-2, -6>. Find -2u + 5v. <-20, -42> <-20, 0> <0, 18> <-6, 0> 2.) Find the dot product, a · b. a = 6i + 5j, b = -5i + 4j 50 <1, 9> -10 <-30, 20> 3.) Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <7, 2>, v = <21, 6> Neither Orthogonal Parallel None of these
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@DanJS
anonymous
  • anonymous
@Loser66
DanJS
  • DanJS
yeah

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More answers

DanJS
  • DanJS
You can add similar dimensions for vectors, and you can multiply a vector by a constant scalar....
anonymous
  • anonymous
@SolomonZelman
DanJS
  • DanJS
c* =
DanJS
  • DanJS
+ =
DanJS
  • DanJS
those are the two rules for part 1
anonymous
  • anonymous
i literally hv no clue how to get an answer
DanJS
  • DanJS
ok.. , here is the first step, replacing u and v with the vectors given -2u + 5v = -2*<5, 6> + 5*<-2, -6>
DanJS
  • DanJS
Now you can, by the first rule i gave, distribute the numbers into the vectors...
anonymous
  • anonymous
is it A?
DanJS
  • DanJS
havent looked at answers , not sure
DanJS
  • DanJS
-2u + 5v = -2*<5, 6> + 5*<-2, -6> = <-10, -12> + < -10, -30>
DanJS
  • DanJS
now use rule 2 that i gave
DanJS
  • DanJS
<-10, -12> + < -10, -30> = <-10+(-10) , -12 + (-30) >
Loser66
  • Loser66
@em2000 It is not hard, please learn how to solve it rather than rely on others. Follow @DanJS and you can do whatever you like. Please, don't just guess the answer. YOu CAN do it by yourself.:)
anonymous
  • anonymous
thank u @DanJS
anonymous
  • anonymous
for #2 i got 50 and #3 i got neither, did u get those?
DanJS
  • DanJS
2-dimensional dot product for part 2 a = <6 , 5> b = <-5 , 4> a * b = 6*-5 + 5*4 Dot product, just add the product of each dimension
anonymous
  • anonymous
-10?
DanJS
  • DanJS
right
anonymous
  • anonymous
awesome, is 3 wrong?
DanJS
  • DanJS
For part 3, the notes to remember are, if for 2 vectors A and B A * B = 0 They are Orthogonal One is a scalar multiple of the other, they are parallel, B = k*A or A = k*B
anonymous
  • anonymous
so they def not orthogonal
DanJS
  • DanJS
hint, the dot product is not zero, and try multiplying the first vector by 3
anonymous
  • anonymous
ohhh theyre parallel!!
DanJS
  • DanJS
yep
anonymous
  • anonymous
thank u so much you are great!!!
DanJS
  • DanJS
no prob, numbers are meaningless, just remember the 3 or 4 rules... good luck

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