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anonymous

  • one year ago

Using the completing-the-square method, find the vertex of the function f(x) = –3x2 + 6x − 2 and indicate whether it is a minimum or a maximum and at what point.

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  1. anonymous
    • one year ago
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    i know you first put it in vertex form, but then how do you decide the max or mini thing

  2. anonymous
    • one year ago
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    https://www.khanacademy.org/math/algebra/quadratics/features-of-quadratic-functions/v/ex3-completing-the-square Here's a video on how to do them

  3. Mehek14
    • one year ago
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    @mollzlask do you know how to find a vertex?

  4. anonymous
    • one year ago
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    once you get it in vertex form, yes

  5. Mehek14
    • one year ago
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    how about with the formula \(x=\dfrac{-b}{2a}\)

  6. anonymous
    • one year ago
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    oh lol how

  7. anonymous
    • one year ago
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    so with that the vertex is 1,1 right?

  8. Mehek14
    • one year ago
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    the original equation is \(ax^2+bx+c=0\) in the equation you have, a = -3 , b = 6 , c = -2

  9. Mehek14
    • one year ago
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    yes the vertex is 1,1

  10. anonymous
    • one year ago
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    okay, so is that the minimum then?

  11. Mehek14
    • one year ago
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    look at a in your equation if it is positive, then it opens upwards and (1,1) is the minimum if it is negative, then it opens downwards and (1,1) is the maximum

  12. Mehek14
    • one year ago
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    so what do you have as a in your equation?

  13. anonymous
    • one year ago
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    its positive

  14. Mehek14
    • one year ago
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    first tell me what a is in your equation

  15. Mehek14
    • one year ago
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    it's the coefficient of \(x^2\)

  16. anonymous
    • one year ago
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    3

  17. anonymous
    • one year ago
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    oh wait lol

  18. Mehek14
    • one year ago
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    it has a negative sign in front of it

  19. anonymous
    • one year ago
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    im stupid im sorry

  20. Mehek14
    • one year ago
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    no it's fine

  21. Mehek14
    • one year ago
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    so it is -3

  22. anonymous
    • one year ago
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    thank you for helping me!!

  23. Mehek14
    • one year ago
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    np so since a is negative, the parabola would open downwards, and (1,1) would be the maximum.

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