anonymous
  • anonymous
Using the completing-the-square method, find the vertex of the function f(x) = –3x2 + 6x − 2 and indicate whether it is a minimum or a maximum and at what point.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i know you first put it in vertex form, but then how do you decide the max or mini thing
anonymous
  • anonymous
https://www.khanacademy.org/math/algebra/quadratics/features-of-quadratic-functions/v/ex3-completing-the-square Here's a video on how to do them
Mehek14
  • Mehek14
@mollzlask do you know how to find a vertex?

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anonymous
  • anonymous
once you get it in vertex form, yes
Mehek14
  • Mehek14
how about with the formula \(x=\dfrac{-b}{2a}\)
anonymous
  • anonymous
oh lol how
anonymous
  • anonymous
so with that the vertex is 1,1 right?
Mehek14
  • Mehek14
the original equation is \(ax^2+bx+c=0\) in the equation you have, a = -3 , b = 6 , c = -2
Mehek14
  • Mehek14
yes the vertex is 1,1
anonymous
  • anonymous
okay, so is that the minimum then?
Mehek14
  • Mehek14
look at a in your equation if it is positive, then it opens upwards and (1,1) is the minimum if it is negative, then it opens downwards and (1,1) is the maximum
Mehek14
  • Mehek14
so what do you have as a in your equation?
anonymous
  • anonymous
its positive
Mehek14
  • Mehek14
first tell me what a is in your equation
Mehek14
  • Mehek14
it's the coefficient of \(x^2\)
anonymous
  • anonymous
3
anonymous
  • anonymous
oh wait lol
Mehek14
  • Mehek14
it has a negative sign in front of it
anonymous
  • anonymous
im stupid im sorry
Mehek14
  • Mehek14
no it's fine
Mehek14
  • Mehek14
so it is -3
anonymous
  • anonymous
thank you for helping me!!
Mehek14
  • Mehek14
np so since a is negative, the parabola would open downwards, and (1,1) would be the maximum.

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