A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

MEDALS N BECOMING FAN 1.)Find the first six terms of the sequence. a1 = -3, an = 2 ● an-1 -6, -12, -24, -48, -96, -192 -3, -6, -12, -24, -48, -96 0, 2, -6, -4, -2, 0 -3, -6, -4, -2, 0, 2 2.)Find an explicit rule for the nth term of the sequence. 2, -8, 32, -128, ... an = 2 ● 4^(n+1) an = 2 ● (-4)^n an = 2 ● 4^(n-1 ) an = 2 ● (-4)^(n-1)

  • This Question is Closed
  1. DanJS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    The first sequence, is taking the term before it and multiplying it by 2 every time

  2. DanJS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    starting with -3

  3. DanJS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[a _{2}=2 * a_{2-1}\] a2 would be 2 times a1 a3 would be 2 times a2 a4 would be 2 times a3 . . .

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -6, -12, -24, -48, -96, -192

  5. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    but your first term is?

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    #2 i got an = 2 ● 4^(n-1 )?

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -3, -6, -12, -24, -48, -96

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sry i meant that 1

  9. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yeah that is better

  10. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    and for 2 u got?

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is my answer for 2 correct?

  12. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you are multiplying times what every time?

  13. DanJS
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Since they gave you multiple choice, you can try each one and really know nothing..

  14. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    (the form is a\(_{\rm n}\)=(a\(_{\rm 1}\))•r\(^{\rm n-1}\) ) r - common ratio - (the number by which you multiply each time)

  15. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    in this case: 2, -8, 32, -128 you are multiplying times 4? That would be close, but not exactly right, because your values are changing signs (they alternate)

  16. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    2 • what = -8? -8• what = 32

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    an = 2 ● (-4)^n @SolomonZelman

  18. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ok, i am not going to tell you right or wrong, but this is what I will say \(a_1=2\cdot (-4)^{1}\) \(a_1=2\cdot(-4)\) \(a_1=-8\)

  19. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    but -8 is the second term, not the first

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh so it has to be this one an = 2 ● (-4)^(n-1)

  21. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    now, \(a_n=2\cdot(-4)^{n-1}\) \(a_2=2\cdot(-4)^{2-1}=2\cdot (-4)^1=-8\) AND \(a_1=2\cdot(-4)^{1-1}=2\cdot (-4)^0=2 \cdot 1 = 2\). ---------------------------------- YES IT HAS TO BE \(a_n=2\cdot(-4)^{n-1}\)

  22. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    u r done with this question:)

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank u!

  24. SolomonZelman
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Anytime!

  25. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.