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anonymous
 one year ago
MEDALS N BECOMING FAN
1.)Find the first six terms of the sequence.
a1 = 3, an = 2 ● an1
6, 12, 24, 48, 96, 192
3, 6, 12, 24, 48, 96
0, 2, 6, 4, 2, 0
3, 6, 4, 2, 0, 2
2.)Find an explicit rule for the nth term of the sequence.
2, 8, 32, 128, ...
an = 2 ● 4^(n+1)
an = 2 ● (4)^n
an = 2 ● 4^(n1 )
an = 2 ● (4)^(n1)
anonymous
 one year ago
MEDALS N BECOMING FAN 1.)Find the first six terms of the sequence. a1 = 3, an = 2 ● an1 6, 12, 24, 48, 96, 192 3, 6, 12, 24, 48, 96 0, 2, 6, 4, 2, 0 3, 6, 4, 2, 0, 2 2.)Find an explicit rule for the nth term of the sequence. 2, 8, 32, 128, ... an = 2 ● 4^(n+1) an = 2 ● (4)^n an = 2 ● 4^(n1 ) an = 2 ● (4)^(n1)

This Question is Closed

DanJS
 one year ago
Best ResponseYou've already chosen the best response.2The first sequence, is taking the term before it and multiplying it by 2 every time

DanJS
 one year ago
Best ResponseYou've already chosen the best response.2\[a _{2}=2 * a_{21}\] a2 would be 2 times a1 a3 would be 2 times a2 a4 would be 2 times a3 . . .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06, 12, 24, 48, 96, 192

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2but your first term is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0#2 i got an = 2 ● 4^(n1 )?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03, 6, 12, 24, 48, 96

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2yeah that is better

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2and for 2 u got?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is my answer for 2 correct?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2you are multiplying times what every time?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.2Since they gave you multiple choice, you can try each one and really know nothing..

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2(the form is a\(_{\rm n}\)=(a\(_{\rm 1}\))•r\(^{\rm n1}\) ) r  common ratio  (the number by which you multiply each time)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2in this case: 2, 8, 32, 128 you are multiplying times 4? That would be close, but not exactly right, because your values are changing signs (they alternate)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.22 • what = 8? 8• what = 32

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0an = 2 ● (4)^n @SolomonZelman

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2ok, i am not going to tell you right or wrong, but this is what I will say \(a_1=2\cdot (4)^{1}\) \(a_1=2\cdot(4)\) \(a_1=8\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2but 8 is the second term, not the first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so it has to be this one an = 2 ● (4)^(n1)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2now, \(a_n=2\cdot(4)^{n1}\) \(a_2=2\cdot(4)^{21}=2\cdot (4)^1=8\) AND \(a_1=2\cdot(4)^{11}=2\cdot (4)^0=2 \cdot 1 = 2\).  YES IT HAS TO BE \(a_n=2\cdot(4)^{n1}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2u r done with this question:)
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