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anonymous
 one year ago
describe how the graph of y+x^2 can be transformed to the graph of the given equation.
y=x^212
@ganeshie8 @hero @myininaya @pooja195 @michele_laino @campbell_st @solomonzelman @loser66 @ligi0210 @mathstudent55 @e.mccormick
anonymous
 one year ago
describe how the graph of y+x^2 can be transformed to the graph of the given equation. y=x^212 @ganeshie8 @hero @myininaya @pooja195 @michele_laino @campbell_st @solomonzelman @loser66 @ligi0210 @mathstudent55 @e.mccormick

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u show me step by step @Loser66

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1If you have any function, such as y = f(x), and you add a constant to the right side, and the function becomes y = f(x) + k, then the graph shifts k units vertically.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it shifts up 12 units right? @mathstudent55

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u just tell me if I'm right @Loser66

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1In your case, k = 12, so it shifts 12 units down.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 can you help me with a quick question please :)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1y = x^2 compared to y = x^2  12 Your function can be written as: y = x^2 + (12) Since k = 12, a negative number, the shift is down 12 units.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1hint: we have these graphs: dw:1437939534222:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1they are more precise than the first ones which I have made @Loser66

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the problem says we start from y=x^2
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