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anonymous

  • one year ago

describe how the graph of y+x^2 can be transformed to the graph of the given equation. y=x^2-12 @ganeshie8 @hero @myininaya @pooja195 @michele_laino @campbell_st @solomonzelman @loser66 @ligi0210 @mathstudent55 @e.mccormick

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  1. anonymous
    • one year ago
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    can u show me step by step @Loser66

  2. mathstudent55
    • one year ago
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    If you have any function, such as y = f(x), and you add a constant to the right side, and the function becomes y = f(x) + k, then the graph shifts k units vertically.

  3. anonymous
    • one year ago
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    so it shifts up 12 units right? @mathstudent55

  4. anonymous
    • one year ago
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    @Loser66

  5. anonymous
    • one year ago
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    can u just tell me if I'm right @Loser66

  6. mathstudent55
    • one year ago
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    In your case, k = -12, so it shifts 12 units down.

  7. anonymous
    • one year ago
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    @mathstudent55 can you help me with a quick question please :)

  8. mathstudent55
    • one year ago
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    y = x^2 compared to y = x^2 - 12 Your function can be written as: y = x^2 + (-12) Since k = -12, a negative number, the shift is down 12 units.

  9. Michele_Laino
    • one year ago
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    hint: we have these graphs: |dw:1437939534222:dw|

  10. Michele_Laino
    • one year ago
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    they are more precise than the first ones which I have made @Loser66

  11. Michele_Laino
    • one year ago
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    the problem says we start from y=x^2

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