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anonymous

  • one year ago

MEDALS N BECOMING A FAN 1.)Three resistors 2.5 Ω, 3.5 Ω and 4 Ω are connected in parallel. What is the equivalent resistance? 0.94 Ω 9.4 Ω 1.1 Ω 10 Ω 2.) How long would it take for 3.5 C of charge to pass through a cross-sectional area of a wire in which a current of 5 mA passes? 7 s 70 s 700 s 1428 s

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  1. anonymous
    • one year ago
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    @SolomonZelman @ash2326

  2. anonymous
    • one year ago
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    @DanJS

  3. anonymous
    • one year ago
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    @Loser66

  4. Loser66
    • one year ago
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    Parallel circuit for resistors formula \(\dfrac{1}{R_{total}}= \dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}\)

  5. anonymous
    • one year ago
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    0.94 Ω

  6. anonymous
    • one year ago
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    #2 is the one im really stuck on

  7. Loser66
    • one year ago
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    put them in to get \(\dfrac{1}{R_total} =\dfrac{1}{2.5}+\dfrac{1}{3.5}+\dfrac{1}{4}= \dfrac{131}{140}\) hence \(R_{total}= \dfrac{140}{131}=1.06\)

  8. Loser66
    • one year ago
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    Actually, I forgot all of my physics knowledge hehehe... have to rely on others.

  9. anonymous
    • one year ago
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    1 Amp = 1 C/s. Therefore\[I=\frac{ q }{ \Delta t }\]You're given q and I, solve for delta t. Don't forget that I is given in mA. It must be converted to A.

  10. anonymous
    • one year ago
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    is it 70? @ospreytriple

  11. anonymous
    • one year ago
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    Not quite.\[\Delta t = \frac{ q }{ I } = \frac{3.5\text{ C}}{0.005 \text{ A}} = ?\]

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