anonymous
  • anonymous
HELP MEDALS N FAN 34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit? 57 46 115 58 36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit? 4 Ω; 1.5 A 18 Ω; 1.5 A 18 Ω; 0.34 A 4 Ω; 0.7 A
Physics
chestercat
  • chestercat
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anonymous
  • anonymous
i need 36
anonymous
  • anonymous
parallel resistance: \[R = \frac{ 6 \times 12 }{ 6+12 }\]
anonymous
  • anonymous
then use V = IR for the current

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anonymous
  • anonymous
what is I and R?
anonymous
  • anonymous
is that 6 and 12
anonymous
  • anonymous
r is resistance, I is current. The 6 and 12 come from the resistors in the problem
anonymous
  • anonymous
4 Ω; 1.5 A is this the answer
anonymous
  • anonymous
yes or no is ok
anonymous
  • anonymous
yes
anonymous
  • anonymous
thank u
radar
  • radar
No. 34. To solve this doe the following steps 1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts 2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.
radar
  • radar
Ohm's Law: E = IR or voltage equal to current (i) times Resistance (R)

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