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anonymous

  • one year ago

HELP MEDALS N FAN 34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit? 57 46 115 58 36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit? 4 Ω; 1.5 A 18 Ω; 1.5 A 18 Ω; 0.34 A 4 Ω; 0.7 A

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  1. anonymous
    • one year ago
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    i need 36

  2. anonymous
    • one year ago
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    parallel resistance: \[R = \frac{ 6 \times 12 }{ 6+12 }\]

  3. anonymous
    • one year ago
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    then use V = IR for the current

  4. anonymous
    • one year ago
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    what is I and R?

  5. anonymous
    • one year ago
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    is that 6 and 12

  6. anonymous
    • one year ago
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    r is resistance, I is current. The 6 and 12 come from the resistors in the problem

  7. anonymous
    • one year ago
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    4 Ω; 1.5 A is this the answer

  8. anonymous
    • one year ago
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    yes or no is ok

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    thank u

  11. radar
    • one year ago
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    No. 34. To solve this doe the following steps 1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts 2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.

  12. radar
    • one year ago
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    Ohm's Law: E = IR or voltage equal to current (i) times Resistance (R)

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