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anonymous
 one year ago
HELP MEDALS N FAN
34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit?
57
46
115
58
36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit?
4 Ω; 1.5 A
18 Ω; 1.5 A
18 Ω; 0.34 A
4 Ω; 0.7 A
anonymous
 one year ago
HELP MEDALS N FAN 34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit? 57 46 115 58 36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit? 4 Ω; 1.5 A 18 Ω; 1.5 A 18 Ω; 0.34 A 4 Ω; 0.7 A

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0parallel resistance: \[R = \frac{ 6 \times 12 }{ 6+12 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then use V = IR for the current

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0r is resistance, I is current. The 6 and 12 come from the resistors in the problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 Ω; 1.5 A is this the answer

radar
 one year ago
Best ResponseYou've already chosen the best response.1No. 34. To solve this doe the following steps 1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts 2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.

radar
 one year ago
Best ResponseYou've already chosen the best response.1Ohm's Law: E = IR or voltage equal to current (i) times Resistance (R)
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