## anonymous one year ago HELP MEDALS N FAN 34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit? 57 46 115 58 36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit? 4 Ω; 1.5 A 18 Ω; 1.5 A 18 Ω; 0.34 A 4 Ω; 0.7 A

1. anonymous

i need 36

2. anonymous

parallel resistance: $R = \frac{ 6 \times 12 }{ 6+12 }$

3. anonymous

then use V = IR for the current

4. anonymous

what is I and R?

5. anonymous

is that 6 and 12

6. anonymous

r is resistance, I is current. The 6 and 12 come from the resistors in the problem

7. anonymous

4 Ω; 1.5 A is this the answer

8. anonymous

yes or no is ok

9. anonymous

yes

10. anonymous

thank u

No. 34. To solve this doe the following steps 1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts 2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.