HELP MEDALS N FAN
34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit?
36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit?
4 Ω; 1.5 A
18 Ω; 1.5 A
18 Ω; 0.34 A
4 Ω; 0.7 A
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what is I and R?
is that 6 and 12
r is resistance, I is current. The 6 and 12 come from the resistors in the problem
4 Ω; 1.5 A
is this the answer
yes or no is ok
No. 34. To solve this doe the following steps
1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts
2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.
Ohm's Law: E = IR or voltage equal to current (i) times Resistance (R)