itsmichelle29 one year ago What is the sum of a 6-term geometric series if the first term is 21 and the last term is 1,240,029? 1,395,030 1,461,460 1,527,890 1,594,320

well you need to find the value of the common ratio. you can do this by using the formula $a_{n} = a_{1} \times r^{n - 1}$ so using the information $1240029 = 21\times r^5$ you need to solve this equation for r then the sum of 6 terms is $s_{6} = \frac{21( 1 - r^6)}{1 - r}$