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anonymous
 one year ago
Can someone help me with this?
√45n^5
anonymous
 one year ago
Can someone help me with this? √45n^5

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\sqrt{45n^5}\) like this?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{black}{ \displaystyle \sqrt{45n^5}=\sqrt{9\cdot 5 \cdot n^4\cdot n} =\sqrt{9\cdot n^4}~\cdot ~\sqrt{5\cdot n}=\sqrt{9} \cdot \sqrt{ n^4}~\cdot ~\sqrt{5\cdot n} }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1that is how i brake them down.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1what is √9, can you tell me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did we lose an n from n^5?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1we didn't, all I did is used the fact that \(n^5=n^{4+1}=n^4\cdot n^1=n^4\cdot n\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1and of course, I rearranged them putting the terms that can be simplified in the beginning and then the terms that can't be simplified

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt{n^4}\) is same as \(\sqrt[2]{n^4}\) and that is =\(n^{4/2}={\rm to~what?}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1ok, did you get up to finding the \(\sqrt{n^4}\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope don't understand what's going on this time.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt{n^4}=\sqrt[2]{n^4}\) this is because whenever the root is not specificed, it is 2 (i.e. SQUARE root)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1now, applying the rule: \(\sqrt[c]{a^b}=a^{b/c}\) we get that \(\sqrt[2]{n^4}=n^{4/2}=n^{2/1}=n^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, didn't know that.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1We had: \(\color{black}{ \displaystyle \sqrt{9} \cdot \sqrt{ n^4}~\cdot ~\sqrt{5\cdot n} }\) and now we had: \(\color{black}{ \displaystyle3 \cdot n^2\cdot ~\sqrt{5\cdot n} }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1oh, now you know.... :0

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{black}{ \displaystyle3 \cdot n^2\cdot ~\sqrt{5\cdot n} }\) is just same as \(\color{black}{ \displaystyle3 n^2~\sqrt{5 n} }\) \(\bf ... \)yw
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