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your boundaries are
\(y=x^3\) and \(y=16x\)
and it is rotated about the x,axis correct?

x-axis *

yes

that will look like a washer method|dw:1437943945723:dw|

do you know the washer method?

i do but have trouble with the set up

lets find the points where these two functions intersect

16x=x³
16=x²
(and disregard negative x solutions because we are only in the 1st quadrant)

x=?

yes, and one more?

yes

So far we know \(\large\color{slate}{\displaystyle\int\limits_{0}^{4}}\)

okay got it and hw to determine inner vs outer for the formula

So, g(x) is always below the f(x) in our case. right?

(you can test it using any value between 0 and 4)

okay great thanks , makes more sense now , you were a big help!!

you are thinking me already, we aren;t done yet, aren we?

thanking*

i just struggle with the set up I just worked out that practice problem and solved it form there

ok, but, just to make sure can you show me your integral that you will set up?