anonymous
  • anonymous
Can i have some help with this? √75 + √3
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
does it help to know that \(75=25\times 3\)?
anonymous
  • anonymous
use the website mathway!
anonymous
  • anonymous
so \[\sqrt{75}=\sqrt{25\times 3}=\sqrt{25}\times \sqrt3\]

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anonymous
  • anonymous
you can enter in the equation and it gives you the answer
anonymous
  • anonymous
you end up with \[5\sqrt3+\sqrt3\] combine like terms to finish
anonymous
  • anonymous
Thanks @ihenandezzi but i'm trying to learn how to do the problem, besides i have the link :)
anonymous
  • anonymous
@satellite73 wouldn't the like term make 6 or do i just write it out and don't add them?
anonymous
  • anonymous
Anyone?
SolomonZelman
  • SolomonZelman
ok, we got to the point of \(5\sqrt{3}+\sqrt{3}\).
SolomonZelman
  • SolomonZelman
Do you know what is 5x+x ?
anonymous
  • anonymous
7?
SolomonZelman
  • SolomonZelman
5x+x=5x+1x=6x ---------------
SolomonZelman
  • SolomonZelman
is that correct?
anonymous
  • anonymous
Yeah
Blake4560
  • Blake4560
yes, 5x+x=6x
SolomonZelman
  • SolomonZelman
5x+x=6x and same way, it follows that 5√3 + √3 = ?
anonymous
  • anonymous
5√6
SolomonZelman
  • SolomonZelman
no
SolomonZelman
  • SolomonZelman
you are not adding inside the square root
anonymous
  • anonymous
So i don't add the 3's
SolomonZelman
  • SolomonZelman
you are adding the "square-root-of-3" five times, PLUS "square-root-of-3" one time.
Blake4560
  • Blake4560
isn't it \[5\sqrt{3}\]
SolomonZelman
  • SolomonZelman
\(5\sqrt{3}+\sqrt{3}=5\sqrt{3}+1\sqrt{3}=?\)
anonymous
  • anonymous
I don't know. guessing 2?
SolomonZelman
  • SolomonZelman
5+1=?
anonymous
  • anonymous
6
SolomonZelman
  • SolomonZelman
5a+1a=?
Blake4560
  • Blake4560
6a
SolomonZelman
  • SolomonZelman
5(something) + 1(something) = ?
anonymous
  • anonymous
Depends on the something.
SolomonZelman
  • SolomonZelman
6(something)
SolomonZelman
  • SolomonZelman
5(something) + 1(something) = 6(something) (as long as we are talking about the same something)
SolomonZelman
  • SolomonZelman
5√3 + 1√3 = ?
anonymous
  • anonymous
Think i said 6..
SolomonZelman
  • SolomonZelman
5√3 + 1√3 = 6 ?
anonymous
  • anonymous
5√6
anonymous
  • anonymous
1√3
SolomonZelman
  • SolomonZelman
5 + 1 = 6 5x + 1x = 6x 5 bees + 1 bee = 6 bees 5a + 1a = 6a 5√3 + 1√3 = 6√3 compare these
anonymous
  • anonymous
6√6
SolomonZelman
  • SolomonZelman
why?
anonymous
  • anonymous
3+3 5+1 6,6
SolomonZelman
  • SolomonZelman
you are adding the number of times of which you have a √3. you have five square roots of 3, and then you add one more square root of 3. how many square roots of 3 do you have together?
anonymous
  • anonymous
6<---
SolomonZelman
  • SolomonZelman
yes, so 5√3 + 1√3 = ?
anonymous
  • anonymous
Do we add the 3's?
anonymous
  • anonymous
if so that would be 6√6
SolomonZelman
  • SolomonZelman
we don't add the square root inside, just 5√3+1√3=(5+1)√3 = 6√
SolomonZelman
  • SolomonZelman
6√3
anonymous
  • anonymous
Okay.

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