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anonymous

  • one year ago

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.

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  1. anonymous
    • one year ago
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    @ganeshie8

  2. anonymous
    • one year ago
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    |dw:1437944587867:dw|

  3. anonymous
    • one year ago
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    ok

  4. anonymous
    • one year ago
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    angle should be easy enough to find with your eyeballs

  5. anonymous
    • one year ago
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    45

  6. anonymous
    • one year ago
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    oh no

  7. anonymous
    • one year ago
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    |dw:1437944669057:dw|

  8. anonymous
    • one year ago
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    225

  9. anonymous
    • one year ago
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    if you are dealing in degrees and not radians, you can use \(-45^\circ\) if you like

  10. anonymous
    • one year ago
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    degrees but my answers are: (3 square root of 2, 315°), (-3 square root of 2, 135°) (3 square root of 2, 225°), (-3 square root of 2, 45°) (3 square root of 2, 45°), (-3 square root of 2, 225°) (3 square root of 2, 135°), (-3 square root of 2, 315°)

  11. anonymous
    • one year ago
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    or if you want the positive one, use \(360-45=315\)

  12. anonymous
    • one year ago
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    distance is \(3\sqrt2\) for sure

  13. anonymous
    • one year ago
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    ok so its the first one?

  14. anonymous
    • one year ago
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    so one answer could be \((3\sqrt2,315^\circ)\)

  15. anonymous
    • one year ago
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    yeah go with the first one

  16. anonymous
    • one year ago
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    ok thanks

  17. anonymous
    • one year ago
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    yw

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