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anonymous

  • one year ago

Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = -2 A) x = 0 B) x = 2 C) There is no x value as there is no solution. D) x can be any value as there is an infinite number of solutions.

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  1. anonymous
    • one year ago
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    @team_cuban

  2. anonymous
    • one year ago
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    I am sorry I forgot how to do system of equations by substitution unfortunately.

  3. anonymous
    • one year ago
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    do you know anyone who is good at these and could help me out?

  4. anonymous
    • one year ago
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    @pooja195 @welshfella

  5. anonymous
    • one year ago
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    These people may be able to help.

  6. pooja195
    • one year ago
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    Whats the opposite of 2?

  7. pooja195
    • one year ago
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    any ideas?

  8. anonymous
    • one year ago
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    -2

  9. pooja195
    • one year ago
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    good so we multiply -2(2x + y = 1) 4x + 2y = -2 \[\huge~\rm~-2(2x + y = 1) \]

  10. pooja195
    • one year ago
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    Distribute

  11. anonymous
    • one year ago
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    I have no idea

  12. pooja195
    • one year ago
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    -2 x 2 = ?

  13. anonymous
    • one year ago
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    -4

  14. pooja195
    • one year ago
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    -2 x y = ?

  15. anonymous
    • one year ago
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    I don't know

  16. pooja195
    • one year ago
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    -2(2x + y = 1) 4x + 2y = -2 \[\huge~\rm~-2(2x + y = 1) \] \(\huge\color{red}{-4x-2y=-2}\)

  17. pooja195
    • one year ago
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    −4x−2y=−2 4x+2y=−2 Heres the fun part :D -4+4=? -2+2=? -2+-2=?

  18. anonymous
    • one year ago
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    can you do that for me... im still a little lost..

  19. pooja195
    • one year ago
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    -4+4=?

  20. anonymous
    • one year ago
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    0

  21. pooja195
    • one year ago
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    -2+2=?

  22. anonymous
    • one year ago
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    0

  23. pooja195
    • one year ago
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    -2+-2?

  24. anonymous
    • one year ago
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    -4

  25. pooja195
    • one year ago
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    When we have a number = a DIFFERENT number we have no solution its not possible to solve 0=-4 would make it so that there is no solution

  26. anonymous
    • one year ago
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    so C?

  27. pooja195
    • one year ago
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    ye

  28. anonymous
    • one year ago
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    See @pooja195 is amazing in Algebra. And I am great in geometry. GOOD WORK @pooja195

  29. pooja195
    • one year ago
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    :) thanks :)

  30. anonymous
    • one year ago
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    No Problem

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