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anonymous

  • one year ago

Please help with a pre calc question. I will fan and medal best response.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @satellite73

  3. anonymous
    • one year ago
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    @ganeshie8

  4. anonymous
    • one year ago
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    The equation of an ellipse centered at the origin is \[\frac{ x^2 }{ a^2}+\frac{ y^2 }{ b^2 }=1\] We know three points (0, 58), (21, 29), and (-21,29). If you substitute the points you should be able to solve for a and b.

  5. anonymous
    • one year ago
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    So: ((21^2)/a^2) +((29^2)/b^2) = 1?

  6. anonymous
    • one year ago
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    not really following you here... sorry

  7. anonymous
    • one year ago
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    yes that's right. And if you use (0,58) you can eliminate the x² part, which allows you to solve for b

  8. anonymous
    • one year ago
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    I'm sorry but can you just show me the steps with the information. Once I've done it once, it will make sense but right now I just don't get it.

  9. anonymous
    • one year ago
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    @Loser66 can you help?

  10. anonymous
    • one year ago
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    \[\frac{ 0^2 }{ a^2 }+\frac{ 58^2 }{ b^2 }=1\] \[\frac{ 58^2 }{ b^2 }=1\] Now you can solve for b

  11. anonymous
    • one year ago
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    wouldn't that mean that b=58?

  12. anonymous
    • one year ago
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    yes.

  13. anonymous
    • one year ago
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    oh ok. lol so how about finding a

  14. anonymous
    • one year ago
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    now put 58 into the equation you made above. \[\frac{ 21^2 }{ a^2 }+\frac{ 29^2 }{ 58^2 }=1\]

  15. anonymous
    • one year ago
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    now I just plug in a different pair of coordinates with b = 58?

  16. anonymous
    • one year ago
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    ok got it that all i need thanks

  17. anonymous
    • one year ago
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    you're welcome

  18. anonymous
    • one year ago
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    @peachpi sorry dude I thought I could get through the rest of the problem by myself but I got stuck can you help me finish it?

  19. anonymous
    • one year ago
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    @Loser66 can you help me finish the problem?

  20. anonymous
    • one year ago
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    I got this far: First find b from: (0^2/a^2) + (58^2/b^2) = 1 58^2/b^2 = 1 b = 58 Now find a: (21^2/a^2) + (29^2/58^2) = 1 (21^2/a^2) + 1/4 = 1 (21^2/a^2) = 3/4 or 0.75

  21. Loser66
    • one year ago
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    @peachpi please finish it. I didn't follow the stuff.

  22. anonymous
    • one year ago
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    he went offline

  23. anonymous
    • one year ago
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    |dw:1437955365294:dw|

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