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anonymous
 one year ago
Please help with a pre calc question. I will fan and medal best response.
anonymous
 one year ago
Please help with a pre calc question. I will fan and medal best response.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation of an ellipse centered at the origin is \[\frac{ x^2 }{ a^2}+\frac{ y^2 }{ b^2 }=1\] We know three points (0, 58), (21, 29), and (21,29). If you substitute the points you should be able to solve for a and b.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So: ((21^2)/a^2) +((29^2)/b^2) = 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not really following you here... sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that's right. And if you use (0,58) you can eliminate the x² part, which allows you to solve for b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry but can you just show me the steps with the information. Once I've done it once, it will make sense but right now I just don't get it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 can you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 0^2 }{ a^2 }+\frac{ 58^2 }{ b^2 }=1\] \[\frac{ 58^2 }{ b^2 }=1\] Now you can solve for b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldn't that mean that b=58?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok. lol so how about finding a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now put 58 into the equation you made above. \[\frac{ 21^2 }{ a^2 }+\frac{ 29^2 }{ 58^2 }=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now I just plug in a different pair of coordinates with b = 58?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok got it that all i need thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi sorry dude I thought I could get through the rest of the problem by myself but I got stuck can you help me finish it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 can you help me finish the problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got this far: First find b from: (0^2/a^2) + (58^2/b^2) = 1 58^2/b^2 = 1 b = 58 Now find a: (21^2/a^2) + (29^2/58^2) = 1 (21^2/a^2) + 1/4 = 1 (21^2/a^2) = 3/4 or 0.75

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi please finish it. I didn't follow the stuff.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437955365294:dw
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