## anonymous one year ago Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0

1. IrishBoy123

"(sin x)(cos x) " you can make this a double angle in sin or you can just go through and work out when either sinx= or cos x = 0, because the other is always -1 < < 1 do you have a preference?

2. anonymous

I actually have a clue with this, but I just want to make sure I was correct. I made sin x=0 and cos x=0, so my answers are 0, pi/2,pi, 3pi/2

3. IrishBoy123

what about $$2 \pi$$?

4. anonymous

|dw:1437946653297:dw|

5. anonymous

Oh yeah right. I was looking at my unit circle and I completely forgot to look at 360 (2pi) because it lies the same with 0 degree.

6. anonymous

7. anonymous

Uhm I still don't know if I get it right?

8. anonymous

|dw:1437947058493:dw|

9. anonymous

insert 0,1,2,3,4 to p

10. anonymous

SO I was right then?

11. IrishBoy123

@mathway close *your* question when you are happy to close *your* question :p you point about 0 coinciding with 2 pi is well made but i'd say that the interval is 0 to 2 pi so it would be right to list 2 pi also; though it is your prerogative well done and thanks

12. anonymous

@IrishBoy123 This was already closed. :P

13. anonymous

@mathway dont take this the wrong way but you're beautiful

14. anonymous

@Zupari I don't think so, but thank you haha. You're beautiful, too!