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anonymous

  • one year ago

Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0

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  1. IrishBoy123
    • one year ago
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    "(sin x)(cos x) " you can make this a double angle in sin or you can just go through and work out when either sinx= or cos x = 0, because the other is always -1 < < 1 do you have a preference?

  2. anonymous
    • one year ago
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    I actually have a clue with this, but I just want to make sure I was correct. I made sin x=0 and cos x=0, so my answers are 0, pi/2,pi, 3pi/2

  3. IrishBoy123
    • one year ago
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    what about \(2 \pi\)?

  4. anonymous
    • one year ago
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    |dw:1437946653297:dw|

  5. anonymous
    • one year ago
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    Oh yeah right. I was looking at my unit circle and I completely forgot to look at 360 (2pi) because it lies the same with 0 degree.

  6. anonymous
    • one year ago
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    please close the question

  7. anonymous
    • one year ago
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    Uhm I still don't know if I get it right?

  8. anonymous
    • one year ago
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    |dw:1437947058493:dw|

  9. anonymous
    • one year ago
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    insert 0,1,2,3,4 to p

  10. anonymous
    • one year ago
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    SO I was right then?

  11. IrishBoy123
    • one year ago
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    @mathway close *your* question when you are happy to close *your* question :p you point about 0 coinciding with 2 pi is well made but i'd say that the interval is 0 to 2 pi so it would be right to list 2 pi also; though it is your prerogative well done and thanks

  12. anonymous
    • one year ago
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    @IrishBoy123 This was already closed. :P

  13. anonymous
    • one year ago
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    @mathway dont take this the wrong way but you're beautiful

  14. anonymous
    • one year ago
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    @Zupari I don't think so, but thank you haha. You're beautiful, too!

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